I can't answer this question if we don't know by what scale the cylinder's radius was reduced. Luckily, I found the same problem that says the radius was reduced to 2/5. So, we find the ratio of both volumes.
V₁ = πr₁²h₁
V₂ = πr₂²h₂
where r₂ = 2/5*r₁ and h₂ = 4h₁
V₂/V₁ = π(2/5*r₁ )²(4h₁)/πr₁²h₁= 8/5 or 1.6
<em>Thus, the volume has increased more by 60%.</em>
You would need four busses
Answer:
26+a
Step-by-step explanation:
(12+a)+14
(12+14)+a
26+a
Answer:
Step-by-step explanation:
![\frac{1}{x}+\frac{1}{3x}=5\\\\\frac{1*3}{x*3}+\frac{1}{3x}=5\\\\\frac{3}{3x}+\frac{1}{3x}=5\\\\\frac{4}{3x}=5\\\\4=5*3x\\\\4=15x\\\\\frac{4}{15}=x](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7B3x%7D%3D5%5C%5C%5C%5C%5Cfrac%7B1%2A3%7D%7Bx%2A3%7D%2B%5Cfrac%7B1%7D%7B3x%7D%3D5%5C%5C%5C%5C%5Cfrac%7B3%7D%7B3x%7D%2B%5Cfrac%7B1%7D%7B3x%7D%3D5%5C%5C%5C%5C%5Cfrac%7B4%7D%7B3x%7D%3D5%5C%5C%5C%5C4%3D5%2A3x%5C%5C%5C%5C4%3D15x%5C%5C%5C%5C%5Cfrac%7B4%7D%7B15%7D%3Dx)
x = 4/15
![\frac{3}{4}x=\frac{3}{4}*\frac{4}{15}\\\\=\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7Dx%3D%5Cfrac%7B3%7D%7B4%7D%2A%5Cfrac%7B4%7D%7B15%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B5%7D)