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Trava [24]
3 years ago
7

!*I NEED HELP AND QUICK*!

Mathematics
1 answer:
rewona [7]3 years ago
5 0
1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2

3) (11 1/2)*12 area of the one  type of the wall, there are 2 such walls
 (11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2

Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476

Tamara needs total 476  square feet, which is less than 480 square feet, so she has enough paint.



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Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

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