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3 years ago

3 x 5 x 2 uygnkuhgkhgiyhbkhbkgy

Mathematics

2 answers:

makkiz [27]3 years ago

7 0

The answer is 30.
Hope this helps

Maru [420]3 years ago

3 0

Answer:

30 is the answer hope this helps!!

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What is the last operation to be performed when finding the value of this expression?

MArishka [77]

To find out the last operation, we must solve the entire problem.

We are given:

$\frac{5+(-8)}{-3+(-9)(-6)}$

Let's simplify the signs so they don't clutter our equation.

$\frac{5-8}{-3+(-9)(-6)}$

We always need to be sure to use PEMDAS. Since there is no expression to solve in parenthesis and no exponents are present, we will move on to multiplication. We can multiply -9 and -6 in the denominator. When we do that, we get:

$\frac{5-8}{-3+54}$

Next, all you need to do is combine like terms in the numerator and the denominator.

$\frac{-3}{51}$

Simplify.

$-\frac{1}{17}$

To answer the question, the last operation to be performed when finding the value would be division.

4 0

3 years ago

A piece of wood is cut into three pieces in the ratio 6: 5: 2. If the log is 61/2 feet long, what will be the length of the long

Lunna [17]

Answer:

14.077 feet to the nearest thousandth.

Step-by-step explanation:

First let's work out the multiplier:

6 + 5 + 2 = 13.

61/2 = 30.5

- so the multiplier is 30.5/13 = 2.34615

The longest piece refers to the 6 in the ratio its length

= 6 * 2.34615

= 14.0769 ft.

3 0

3 years ago

A tank with a capacity of 100 gallons initially contains 50 gallons of water with 10 pounds of salt in solution. fresh water ent

steposvetlana [31]

Let $A(t)$ be the amount of salt (in pounds) in the tank at time $t$ . We're given that $A(0)=10\text{ lb}$ .

The rate at which the amount of salt in the tank changes is given by the ODE

$A'(t)=\dfrac{2\text{ gal}}{1\text{ min}}\cdot\dfrac{0\text{ lb}}{1\text{ gal}}-\dfrac{1\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{50+(2-1)t\text{ gal}}$

$A'(t)+\dfrac{A(t)}{50+t}=0$

$(50+t)A'(t)+A(t)=0$

$\bigg((50+t)A(t)\bigg)'=0$

$(50+t)A(t)=C$

$A(t)=\dfrac C{50+t}$

Given that $A(0)=10$ , we find that

$10=\dfrac C{50+0}\implies C=500$

so that the amount of salt in the tank is described by

$A(t)=\dfrac{500}{50+t}$

The tank will be filled when $50+t=100$ , or after $t=50$ minutes. At this time, the amount of salt in the tank is

$A(50)=\dfrac{500}{50+50}=5\text{ lb}$

7 0

4 years ago

Find the radius and the diameter of the circle

hichkok12 [17]

Answer:

26 inches is diameter

Step-by-step explanation:

d=2r

d=2×13

d=26

4 0

3 years ago