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3 years ago

Due 11:25 AM

Mathematics

1 answer:

Bess [88]3 years ago

5 0

Answer:

Starting from the origin go right 4 units in order to get 4 as your x value and then go down 3 units in order to get -3 as your y value.

Step-by-step explanation:

Do i need to be more specific?

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Y=f(x)=9x^2+18x Axis= Vertex= Y-intercept = X-intercept=

svet-max [94.6K]

Sent a picture of the solution to the problem (s).

3 0

3 years ago

Please help! - - - - -

Jlenok [28]

The answer has to be in y-intercept form. Which is y=mx+b and b can also be neg. y=mx-b. The m is your slope and b is your y-intercept. So A’s slope counting from 3 on the y axis to 1 on the x-axis which is down 2 over 1 so it will be -2/1. And your y intercept is 3. The equation is y=-2x+3. For B its the same thing but no graph. Remember that slope is RISE over RUN. So since the number is on the bottom of the line the rise is 4 and the run is 1. So in this case 10 is your y-intercept. Which means you equation is y=4x+10.

5 0

3 years ago

Find the slope of the line that is (a) parallel and (b) perpendicular to the line through the pair of points.

ddd [48]

Answer:

a) The slope of the line is parallel to the another line m=4

b) The slope of the line is perpendicular to the another line m= $\frac{-1}{4}$

Step-by-step explanation:

Step1:-

Slope of a line :-

If θ is the inclination of a line 'l' then tanθ is called the slope or gradient of the line 'l'.The slope of a line is denoted by m=tanθ

The slope of a line given two points m= $\frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

Parallel lines:-

Two non-vertical lines are parallel if and only if their slopes are parallel

Perpendicular lines:-

Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

$m_{2} = \frac{-1}{m_{1} } \\$

Step 2:-

a)The slope of a line when given two points (-1,-4) and (0,0)

$m = \frac{0-(-4)}{0-(-1)} =4$

Two non-vertical lines are parallel if and only if their slopes are parallel

$m_{1} = m_{2}$

Therefore the slope of the line that is parallel to the another line

$m_{1} =m_{2} =4$

Step 3:-

b) Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

$m_{2} = \frac{-1}{m_{1} } \\$

$m_{2} =\frac{-1}{4}$

Therefore the slope of the line is perpendicular to the another line is

$m=\frac{-1}{4}$

3 0

3 years ago

Read 2 more answers

In a bakery, a bag of bread rolls cost x dollars. A loaf of multi-grain bread costs $2 more than a bag of bread rolls. Mr. Lopez

Vaselesa [24]

Step-by-step explanation:

Cost of bag of bread rolls is x

Multigrain is (+2) more.

So (x+2)

Y can be the number of multigrain loves Mr. Lopez buys.

Answer: y=50/(x+2)

6 0

3 years ago

Complete the equation of the line through (-9,-9) and (-6,0)

Rudik [331]

For this case we have that by definition, the equation of the line of the slope-intersection form is given by:

$y = mx + b$

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis.

According to the data of the statement we have the following points:

$(x_ {1}, y_ {1}): (- 9, -9)\\(x_ {2}, y_ {2}): (- 6,0)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {0 - (- 9)} {- 6 - (- 9)} = \frac { 9} {- 6 + 9} = \frac {9} {3} = 3$

Thus, the equation is of the form:

$y = 3x + b$

We substitute one of the points and find b:

$0 = 3 (-6) + b\\0 = -18 + b\\b = 18$

Finally, the equation is:

$y = 3x + 18$

Answer:

$y = 3x + 18$

7 0

3 years ago