Answer:
![(x - 2)^{2} + (y - 1)^{2} = 17](https://tex.z-dn.net/?f=%28x%20-%202%29%5E%7B2%7D%20%2B%20%28y%20-%201%29%5E%7B2%7D%20%3D%2017)
Step-by-step explanation:
The current equation of the circle is:
⇒ ![x^{2} + y^{2} - 4x - 2y + 10 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20y%5E%7B2%7D%20-%204x%20-%202y%20%2B%2010%20%3D%200)
In order to get it into the standard form;
⇒ ![(x - a)^{2} + (y - b)^{2} = r^{2}](https://tex.z-dn.net/?f=%28x%20-%20a%29%5E%7B2%7D%20%2B%20%28y%20-%20b%29%5E%7B2%7D%20%3D%20r%5E%7B2%7D)
We must complete the square;
⇒ ![(x - 2)^{2} - 4 + (y - 1) - 1 + 10 = 0](https://tex.z-dn.net/?f=%28x%20-%202%29%5E%7B2%7D%20-%204%20%2B%20%28y%20-%201%29%20-%201%20%2B%2010%20%3D%200)
Now, collect like terms and rearrange;
⇒ ![(x - 2)^{2} + (y - 1)^{2} = -5?](https://tex.z-dn.net/?f=%28x%20-%202%29%5E%7B2%7D%20%2B%20%28y%20-%201%29%5E%7B2%7D%20%3D%20-5%3F)
We now know that the Centre is at the point (2, 1).
We can use the distance formula to find the radius;
⇒ ![d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_%7B2%7D%20-%20x_%7B1%7D%29%5E%7B2%7D%20%2B%20%28y_%7B2%7D%20-%20y_%7B1%7D%29%5E%7B2%7D%7D)
⇒ ![d = \sqrt{(6 - 2)^{2} + (2 - 1)^{2}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%286%20-%202%29%5E%7B2%7D%20%2B%20%282%20-%201%29%5E%7B2%7D%7D)
⇒ ![\sqrt{17}](https://tex.z-dn.net/?f=%5Csqrt%7B17%7D)
Therefore the radius squared is 17.
Now substitute into our equation:
⇒ ![(x - 2)^{2} + (y - 1)^{2} = 17](https://tex.z-dn.net/?f=%28x%20-%202%29%5E%7B2%7D%20%2B%20%28y%20-%201%29%5E%7B2%7D%20%3D%2017)
Answer:
h(0) = 10
h(4) = 16
Step-by-step explanation:
h(0) = 2(0)² - 3(0) + 10 = 10
h(4) = 2^4 = 16
Step-by-step explanation:
![\frac{1}{9} = 0.111111111... = 0. \bar1 \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B9%7D%20%20%3D%200.111111111...%20%3D%200.%20%5Cbar1%20%5C%5C%20)
Thus, 1 is the only repeating digit which is repeating infinite number of times.
John gets 12, Walt, Matt, and Richie get 4 each
Answer:
2+x square =274
Step-by-step explanation:
you plug in the numbers you have and make the equation and solve for x
note:
when ever you get x square =# this is you width.
to get the length you square root the number after subtracting 2 from both sides to get the length because it says twice.
I HOPE THAT WILL HELP YOU