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Over [174]
3 years ago
7

(2x^3 - 2x^2) Divide or subtract exponents ?

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0

Answer:

Neither.

Step-by-step explanation:

You can only add exponents when multiple, or subtract when dividing.

Also, 2x^3 and 2x^2 are two different terms, not like terms, so cannot subtract the two.

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To shift the graph of an equation a certain number of units _____, you need to subtract that number from the functions equation
FromTheMoon [43]

Answer:

The correct option is A) Down.

Step-by-step explanation:

A function can be shift vertically up or down by adding some positive or negative constant.

For example:

Consider the figure 1:

The function g(x)=f(x)+k shifted up by <em>k</em> unit. (where <em>k</em> is 1 unit)

Now consider the figure 2:

The function g(x)=f(x)-k shifted down by <em>k</em> unit. (where <em>k</em> is 1 unit)

Which means to shift the graph of an equation certain number of units up, we need to add that number from the functions equation.

Similarly, to shift the graph of an equation certain number of units down, we need to subtract that number from the functions equation.

Therefore, the correct option is A) Down.

3 0
3 years ago
Read 2 more answers
Help solve plz thanks
padilas [110]
The answer is :

b = t - 5 / 4
5 0
3 years ago
Read 2 more answers
If f(x) = 2x2 + bx + c, find the value of "c" that makes the vertex of the given graph the same as the vertex of f(x).
AlekseyPX

Well it was a lucky guess but the answer is 75

8 0
3 years ago
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In the standard (x,y) coordinate plane a right triangle has vertices at (-3,4)(3,4)(3,-4) what is the length in coordinates unit
MAXImum [283]

Given:

The vertices of a right triangle are:

(-3,4),(3,4),(3,-4)

To find:

The length of the hypotenuse of the given right triangle.

Solution:

Let the vertices of the right triangle are A(-3,4),B(3,4),C(3,-4).

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(3-(-3))^2+(4-4)^2}

AB=\sqrt{(3+3)^2+(0)^2}

AB=\sqrt{(6)^2+0}

AB=\sqrt{36}

AB=6

Similarly,

BC=\sqrt{(3-3)^2+(-4-4)^2}

BC=\sqrt{(0)^2+(-8)^2}

BC=\sqrt{64}

BC=8

And,

AC=\sqrt{(3-(-3))^2+(-4-4)^2}

AC=\sqrt{(6)^2+(-8)^2}

AC=\sqrt{36+64}

AC=\sqrt{100}

AC=10

Now, taking sum of squares of two smaller sides, we get

AB^2+BC^2=6^2+8^2

AB^2+BC^2=36+64

AB^2+BC^2=100

AB^2+BC^2=AC^2

By the definition of the Pythagoras theorem, AC is the hypotenuse of the given triangle.

Therefore, the length of the hypotenuse is 10 units.

6 0
3 years ago
How to round 831,756 nears hundred thousand
Anettt [7]

Answer:

800,000

Step-by-step explanation:

If the number was above 850,000 it would round up. If the number was 849,999 or below it would round down. In other words, you look at the number to the right of the hundred thousands place, or the number in the tens of thousands place, and if it is 5 or above you round up. 4 and below you round down.

4 0
2 years ago
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