25 POINTS AND BRAINLIEST PLEASE HELP

From 20 Miles To 11 miles (decrease) Answer??

allochka39001 [22]

20 miles - 11 miles= 9 miles

so 9 mile decrease

7 0

3 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

So

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago

a rectangle has a length of x inches and a width 3 inches less than the length. if the dimensions were doubled , what would be t

iren [92.7K]

Original length: x
original width; x-3
original area: x(x-3)
when the dimensions doubles, that is, increase by a factor of 2, the area increase by 2²
4[x(x-3)]
4x(x-3)=4x²-12x

you can also do it this way:
original length: x doubled: 2x
original width; x-3 doubled: 2(x-3)
new area: 2x[2(x-3)]= 4x²-12x

6 0

4 years ago

A box contains 5 purple marbles, 3 green marbles, and 2 orange marbles. Two consecutive draws are made from the box without plac

lana66690 [7]

There are 2 orange marbles, 3 green marbles, & 5 purple marbles

two consecutives draws without replacement

Orange first, green second

Orange/total = 2/10, or 1/5
green/total - 1 = 3/9, or 1/3
1/5(1/3) = 1/15
There is a 1/15 chance of Orange first, green second

Both marbles are purple
Purple/total = 5/10, or 1/2
Purple/total = 4/9, or 44% chance of both being purple

first is purple, the next is anything but purple
purple/total = 1/2, or 50% chance
(everything - purple)/total = 5/10, or 50% chance
1/2(1/2) = 1/4, or 25% chance of first purple, then anything but purple

hope this helps

4 0

3 years ago

Whoever answer is correct get brainliest

Semmy [17]

Answer: it is c

Step-by-step explanation:

3 0

3 years ago

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