If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
5
Step-by-step explanation:
move the terms
collect like terms
calculate
divide both side
Answer:
it would be y= 3/4x + 2
Step-by-step explanation:
the form is y=mx+b
and you have to set it up as 8y=16-6x
Divide each term
Cancel the common factor of 8.
Divide y by 1
then simplify and turn it into a fraction.
152.5 is 250% of the number, 61
Answer:
25 x 25= you gey ur answer
Step-by-step explanation:
