Ask question

Ask question

All categories

3 years ago

13

The length of a rectangle is represented by 4a + 4b, and its width is represented by 4a − 2b. Enter the polynomial for the perim

eter of the rectangle. What is the minimum perimeter of the rectangle if a = 12 and b is a non-zero whole number?

1 answer:

Pavel [41]3 years ago

4 0

\left[a \right] = \left[ \frac{b}{2}\right][a]=[2b] totally answer

You might be interested in

I need help with this please!!

8090 [49]

Answer:

no solution

Step-by-step explanation:

3 0

3 years ago

Q.The rectangular front windshield of the bus has the length of 1.5√3 m and the width of 1.5 m . The wipers are attached to the

galina1969 [7]

Answer:

Area covered by wiper=area of arc(A0D)+area of traingleAOB+area of arc(BOC)

We know AO and OB are wipers,whose lengths are 1.5

In ∆ABC

AB^2+BC^2=AC^2

(1.5√3)^2+(1.5)^2=(AC)^2

2.25×3+2.25=(AC)^2

2.25×4=AC^2

AC=3

Also AO=1.5

similarly using Pythagoras theorem in ∆OBC

we get

OC=1.5

this shows that point O is the bisector of diagonal AC

so,AO=OC

also from property of rectangle we know that, diagonal bisects each other equally

so,O will also be the bisector of diagonal BD

hence OB=OD=1.5

AC=BD (property of triangle)

AC/2=BD/2

OB=OC,hence OB=OC=OD=OA=1.5=AD=BC

Hence OAD will be an equilateral triangle

so

angle OAD=60

similarly angleOBC=60

area of sector=angle of that sector ×area of circle/360

area of arc(AOD)+arc(BOC)=60/360 ×3.14 ×1.5×1.5 +60/360 ×3.14×1.5×1.5

=2×(60/360)×1.5×1.5

area of triangleAOB=area of rectangle/4 (diagonal divides the rectangle in 4 equal parts)

area of triangle=1.5×1.5√3/4

=>1.5×2.6/4=3.90/4

=0.975 or 0.98(approx)

Area covered by wiper=.98+2×60/360 ×3.14×1.5×1.5

=.98+0.75×3.14=2.35+0.97

=2.35+.98

Percentage of area of windshield covered by wiper=3.3×100/3.9=84.61

hence percentage of area of windshield covered by wiper is 85percent(approx)

plz mark brainlest

5 0

3 years ago

Please help, common assessment quiz question linked with picture

irinina [24]

The dilation is 4. Everything is getting 3 times bigger.

8 0

4 years ago

What did the Japanese adapt from Chinese

Shalnov [3]

I think the answer is Hinduism

8 0

3 years ago

On January 1, 2006, you have $100 in a savings account that earns interest at a rate of 1% per month. On the last day of every m

WINSTONCH [101]

Answer:

The recursive rule for account balance at the beginning of the nth month will be given by $b_{1} = 100$ and $b_{n + 1} = b_{n} + 76$ where, n = 1, 2, 3, .....

Step-by-step explanation:

On January 1, 2006, I have $100 in a savings account that earns interest at a rate of 1% per month. On the last day of every month, I deposit $75 in the account, beginning in January.

So, at the end of the month of January, the added amount to the account is $75 and 1% of $100 i.e. 1$.

Then, total $(75 + 1) = $76 is being added at the end of each month.

So, the recursive rule for account balance at the beginning of the nth month will be given by $b_{1} = 100$ and $b_{n + 1} = b_{n} + 76$ where, n = 1, 2, 3, ..... (Answer)

3 0

3 years ago