1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hoochie [10]
3 years ago
5

Describe how quantity change in relationship to another

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0
It really depends .............
You might be interested in
What was the total for her order?​
Ksenya-84 [330]

Answer:

her total was 11.

Step-by-step explanation:

8 0
2 years ago
What can you conclude about DNA from the idea that it is<br> like a cell's "brain"?
Lena [83]

Answer:

Cells could not function without them

Step-by-step explanation:

3 0
3 years ago
Solve for x -3 + x <br> = - 38
fiasKO [112]

x-3+x=-38

2x-3=-38

2x=3-38=-35

x=-35/2=-17.5

3 0
3 years ago
Read 2 more answers
If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

A2=(4)(x)=4x\ in^2

A3=(x)(7)=7x\ in^2

A4=(4)(7)=28\ in^2

The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

A=A1+A2+A3+A4

For x=2 in

substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

A3=(2)(7)=14\ in^2

A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
HELP ME PLS
mina [271]
Age>8. I think ..............
7 0
3 years ago
Read 2 more answers
Other questions:
  • Write the expression below. Divide 9 by the sum of 6 and 4
    7·1 answer
  • 6. Find the missing value. Show your work.
    10·1 answer
  • A large consumer goods company ran a television advertisement for one of its soap products.
    10·1 answer
  • Jackson drove 1,080 miles<br> in 20 hours. What was his<br> speed in miles per hour?
    15·1 answer
  • PLEASE ANSWER FAST PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! The point (1, −1) is on the terminal side of
    8·1 answer
  • Write the equation of the circle centered at (0,1) with radius 15.
    13·1 answer
  • What is the ratio of cups to quarts in a carton of milk?
    7·1 answer
  • Gabriel has a square canvas that
    11·1 answer
  • I really need help on this question please
    10·1 answer
  • Jocelyn said that the triangle below is not a right triangle. Her work is shown below. Explain what she did wrong and show Jocel
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!