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Novay_Z [31]
3 years ago
11

4p+6-3 combine like terms?

Mathematics
1 answer:
amm18123 years ago
4 0

Answer:

4p+3

Step-by-step explanation:

Because 4 has the variable p next to it, 4 can not be the same as 6 or 3 because they are whole numbers. So the only thing you can do here is 6-3, which is 3.

You might be interested in
Hich two mathematical operations use the commutative property?
Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

multiplication:)

5 0
3 years ago
Please help me answer this question
oee [108]

b is f of g is

equal to -10

6 0
3 years ago
Tom and his bothers caught 100 fish on a weeklong fishing trip. The total weight of the fish was 235 pounds write an expression
gtnhenbr [62]
If the weight of each fish is the same all you need to do is to divide 235 by 100 to get 2.35 pounds per fish.
Hope this helps!
7 0
3 years ago
4 plates and 3 cups cost 20.70 dollars. 5 plates and 4 cups cost 26.40 dollars . each plates cost the same amount as the other p
Basile [38]
Here, we need to construct 2 linear equation.
Let x be the plate and y be the cup.
1) 4x + 3y = 20.70
2) 5x + 4y = 26.40

From equation 1, we solve for y.
3y = 20.70 - 4x
y = (20.70 - 4x) / 3

Substitute into equation 2.
5x + 4((20.70 - 4x) / 3) = 26.40
5x + 27.60 - 5.33x = 26.40
-0.33x = 26.40 - 27.60
-0.33x = -1.2
x = 3.64

We already get value of x. Now, calculate for value of y.
y = (20.70 - 4x) / 3
y = (20.70 - 4(3.64)) / 3
y = 2.05

The cost for 1 plate is 3.64 dollars and 1 cup is 2.05 dollars.
7 0
3 years ago
How do you determine where f(x)=cos^(-1)(lnx) is continuous?
olga nikolaevna [1]
\ln x is continuous over its domain, all real x>0.

Meanwhile, \cos^{-1}y is defined for real -1\le y\le1.

If y=\ln x, then we have -1\le \ln x\le1\implies \dfrac1e\le x\le e as the domain of \cos^{-1}(\ln x).

We know that if f and g are continuous functions, then so is the composite function f\circ g.

Both \cos^{-1}y and \ln x are continuous on their domains (excluding the endpoints in the case of \cos^{-1}y), which means \cos^{-1}(\ln x) is continuous over \dfrac1e.
7 0
3 years ago
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