The equation that best represents the behavior of acetic acid in water is; CH3CO2H + H2O ⇄ CH3CO2− + H3O+.
Acetic acid, like all other acids dissociates in water. The equation for the dissociation of acetic acid in water is; CH3CO2H + H2O ⇄ CH3CO2− + H3O+.
During this dissociation, the acid proton in acetic acid is transferred to water to form the oxonium ion H3O+.
The presence of H3O+ in solution accounts for all the observed properties of acetic acid in solution.
Learn more: brainly.com/question/14072179
Answer:
Energy produced by the chip =10,460 Joules.
Explanation:
The specific heat of water is one calorie/gram ° C = 4.186 joules/gram ° C, which is higher than any other common substance. As a result, water plays a very important role in regulating temperature. The specific heat per gram for water is much greater than that of a metal, as described in the water-metal example. Replace the mass (m), the temperature change (ΔT), and the specific heat (c) of the solution in the equation Q = c x m x ΔT, where Q is the heat absorbed by the solution. For specific heat of water we goes as given in the question 4,184 J/kg°C
Q =4184×0.5×(25-20)
=10,460 Joules.
Thus heat gained by water (Q)= Energy produced by the chip =10,460 Joules.
Omg yes her creepiness makes her 20x better
Answer:
Explanation:
V1/T1 =V2/T2 at constnant pressure
Answer:
0.4951 grams of Zn have been consumed.
Explanation:
Pressure at which gas is collected over water = p = 732 Torr
Vapor pressure of the water = p' = 26.74 Torr
Pressure of hydrogen gas = P
p = P + p'
P = p - p' = 732 Torr - 26.74 Torr = 705.26Torr
P =
1 atm = 760 Torr
Volume of the hydrogen gas = V = 201 mL = 0.201 L
1 mL= 0.001 L
Moles of hydrogen gas = n
Temperature at which hydrogen gas collected = T = 27°C = 27+273 K = 300 K
Using an ideal gas equation:
n = 0.007573 mol
According to recation , 1 mole of hydrgen gas was obtained from 1 mole of zinc,then 0.007573 moles of hydrgen gas will be obtained from;
of zinc
Mass of 0.007573 moles of zinc:
0.007573 mol × 65.38 g/mol = 0.4951 g
0.4951 grams of Zn have been consumed.