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weeeeeb [17]
3 years ago
6

Why does the solution decolorize on standing after the equivalence point has been reached?

Chemistry
2 answers:
Arisa [49]3 years ago
8 0

The equivalence point of a titration is equal to its stoichiometric equivalents of analyte and titrant.

Depending on the concentration of titrant we could be adding little excess of it and this may result in persistence of color of solution. After continuous stirring for a while the excess titrant may react with dissolved CO₂ in air and thus decolorizing the solution.

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Colt1911 [192]3 years ago
3 0

Answer:

The potassium permanganate slowly fades in color as it is dissolved in the water.

Explanation:

Hello,

Perhaps, your talking about a titration that was carried out by using potassium permanganate as the titrant, thus, bringing to bear the fact that the equivalence point of a titration is equal to its stoichiometric equivalents of analyte and titrant, one could state that as the titration is carried out, the potassium permanganate slowly fades in color as it is dissolved in the water after the equivalence point is reached since the formed species become colorless as well.

Best regards.

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2 years ago
An atom or ion has 41 neutrons, 36 protons, and 36 electrons. Identify the element symbol, and determine the mass number
igor_vitrenko [27]

Answer:

Element symbol: Kr.

Mass number: 77.

Charge : 0.

Explanation:

Hello,

In this case, since such substance has the same amount of protons and electrons we can infer it is an atom whose number of neutrons is defined by considering its atomic mass or mass number and atomic number which is actually equal to the number of protons and electrons (36):

neutrons=atomic\ mass - atomic\ number

In such a way, solving for the atomic mass we obtain:

atomic\ mass=neutrons+ atomic\ number\\\\atomic\ mass=41+36=77

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3 years ago
What is the most important factor in determining climates.
Ira Lisetskai [31]

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Rank the ions in each set in order of decreasing size, and explain your ranking:
Valentin [98]

Answer:

a) Se²⁻> S²⁻ > O²

b) Te²⁻ > I- >Cs+

c)  Cs+ > Ba²⁺ > Sr²⁺

Explanation:

(a) Se²⁻, S²⁻, O²⁻

In general, ionic radius decreases with increasing positive charge.

As the charge on the ion becomes more positive, there are fewer electrons.

The ion has a smaller radius. In general, ionic radius increases with increasing negative charge.

For ions of the same charge (e.g. in the same group) the size increases as we go down a group in the periodic table

Se²⁻> S²⁻ > O²

(b) Te²⁻, Cs⁺, I⁻

Te²⁻ > I- >Cs+

Te2- hast the biggest size, because of the double negative charge.

Cs+ has the smallest size since it has the most positive charge, compared to Te2- and I-.

(c) Sr²⁺, Ba²⁺, Cs⁺

Cs+ > Ba²⁺ > Sr²⁺

Cs+ has the biggest size, because its more downward (compared to Sr2+) and more to the left (compared) ot Ba2+.

Sr2+ has the smallest size because it's more upwords (compared to Cs+ and Ba2+)

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