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almond37 [142]
3 years ago
5

which one of the following is not a pure substance? A. Diamond B. water C. Oxygen D. Milk​

Chemistry
1 answer:
Nonamiya [84]3 years ago
8 0

Answer:

Milk

Explanation:

Main compounds of milk are lactose and casein. And it is also called a colloidal mixture (i.e. in which one substance of microscopically dispersed insoluble or soluble particles is suspended throughout another substance). Therefore milk is regarded as a mixture not as a pure substance. So this is the required answer.

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Diamond and graphite are two crystalline forms of carbon. In which form are the bonds between the C atoms arranged at tetrahedra
Fynjy0 [20]

Answer:

The answer is letter A. Diamond

Explanation:

The diamond is a crystalline form of carbon, with a cubic structure, of the sp³ type, that is, each carbon atom of the structure is linked to four other carbon atoms, forming a tetrahedral geometry.

3 0
3 years ago
What is the stoichiometric coefficient for oxygen when the following equation is balanced using the lowest whole-number coeffici
rodikova [14]

Answer:

Option (B) 7

Explanation:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

To know the coefficient of O2 in the above equation, let us balance the equation.

The above equation can be balance as follow:

C3H6O2(l) + O2(g) → CO2(g) + H2O(l)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + H2O(l)

There are 6 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 3 in front of H2O as shown below:

C3H6O2(l) + O2(g) → 3CO2(g) + 3H2O(l)

There are a total of 4 atoms of O on the left side and a total of 9 atoms on the right side. It can be balance by putting 7/2 in front of O2 as show below:

C3H6O2(l) + 7/2O2(g) → 3CO2(g) + 3H2O(l)

Multiply through by 2

2C3H6O2(l) + 7O2(g) → 6CO2(g) + 6H2O(l)

Now, the equation is balanced.

From the balanced equation above, the coefficient of O2 is 7.

7 0
3 years ago
Describe a qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2)
Lady bird [3.3K]

A qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2) is given Ba²⁺(aq) + SO₄²⁻ (aq)  →   BaSO₄(s).

<h3>What is qualitative test?</h3>

Qualitative test measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation of the sample.

<h3>Qualitative test for sulfate in alum crystals </h3>

When an aqueous solution of a barium salt (BaCl₂) is mixed with an aqueous solution containing sulfate, a white precipitate of insoluble BaSO₄ forms according to the net ionic equation given below;

Ba²⁺(aq) + SO₄²⁻ (aq)  →   BaSO₄(s)

Thus, a qualitative test for sulfate in alum crystals using ionic reactions of barium chloride (BaCl2) is given Ba²⁺(aq) + SO₄²⁻ (aq)  →   BaSO₄(s).

Learn more about qualitative test here: brainly.com/question/2109763

#SPJ1

8 0
2 years ago
Which of the following lists the given objects in the correct mass order from lowest to highest?
Mrrafil [7]
Sorry no se inglés
Bdnnfncnfnfnfn
5 0
2 years ago
What does the red represent on the model? *
kaheart [24]
The red is an oxygen molecule. 1 oxygen and 2 hydrogen =h2o or water!
6 0
3 years ago
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