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Nadya [2.5K]
3 years ago
7

What is the approximate volume of a cylinder with a radius of 8 cm and height of 5 cm?

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0
V(cylinder)=πr² *h
r=8 cm
h=5 cm
V(cylinder)=πr² *h =3.14*8²*5= 1004.8 cm³
Answer : E.
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The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is
tensa zangetsu [6.8K]

Answer: 10, 11, & 12

<u>Step-by-step explanation:</u>

Let x represent the age of the youngest child.  

Their ages are consecutive so,

Youngest: x

Middle: x + 1

Oldest: x + 2

The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.

x² = 8(x + 2) + 4

x² = 8x + 16 + 4

x² = 8x + 20

x² - 8x - 20 = 0

(x - 10)(x + 2) = 0

x - 10 = 0     or      x + 2 = 0

  x = 10       or          x = -2

Since age cannot be negative, x = -2 is not valid

So, the Youngest (x) is 10

the Middle (x + 1) is 11

and the Oldest (x + 2) is 12

4 0
3 years ago
Help i’m doing my exam
jolli1 [7]
Dude I don’t think using this for an exam is it but ok
5 0
3 years ago
Read 2 more answers
A board game has a spinner with four different options of how a player can move: move forward 1 space, move forward 2 spaces, mo
leva [86]

The answers are:

A. 7/12

B. 5/12

4 0
2 years ago
4. Find the area of the following composite figure.
inn [45]

Answer:

The area is 136

Step-by-step explanation:

7 x 16 = 112

1/2 x 8 x 6 = 24

24 + 112 = 136

7 0
2 years ago
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Please help me!! Will get brainliest!
makvit [3.9K]
Completing the square follows the principle of taking a x^{2} +bx+c and converting it into (x+ \frac{b}{2})^2+d where d is the 'correctional number' as I like to call it - i.e. the number that converts the expanded bracket into the +c, since the expanded bracket will give us a x^{2} +b.

In this case, 2/2=1 so we have the first part: (w+1)^2.
Expanding this gives us w^2+2w+1. We need c to be 9, so we can just add 8.
Putting this together:

w^2+2w+9=(w+1)^2+8

Now we can solve it more easily.
Rearranging:
(w+1)^2=-8 \\ w+1= +-\sqrt{-8} = +-\sqrt{8}i=+-2 \sqrt{2}i   \\ \boxed{w=-1+ 2\sqrt{2}i\ or\ -1-2 \sqrt{2}i  }
5 0
3 years ago
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