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Helen [10]
3 years ago
5

Six more than a quotient of a number and three is greater than 14

Mathematics
2 answers:
Mashcka [7]3 years ago
6 0
Its actually really simple. x/3 + 6> 14 , or rather, x divided by 3 + 6 is greater than 14
Lorico [155]3 years ago
3 0

Remark

You sure do have to read that a couple of times.

The quotient is an answer after a division takes place So you are dividing x/3

When you have figured out that phrase you add six onto it.

(x/3) + 6 > 14 Subtract 6 from both sides.

(x/3) +6 - 6 > 14 - 6

(x/3) > 8 Now multiply by 3

x > 8*3

x > 24 <<<<<< Answer

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Write an equation of the perpendicular bisector of the line segment whose endpoints are (−1,1) and (7,−5)
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The equation is y = \frac{3}{2} x - \frac{11}{2}

<u>Explanation:</u>

We have to first find the mid-point of the segment, the formula for which is

(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )

So, the midpoint will be (\frac{-1+7}{2} , \frac{1-5}{2} )\\\\

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It is the point at which the segment will be bisected.

Since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula \frac{y_2-y_1}{x_2-x_1}

The slope is \frac{-5-1}{7+1} = -\frac{2}{3}

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of  -\frac{2}{3} is \frac{3}{2}

To write an equation, substitute the values in y = mx + c

WHere,

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Solving for c:

-1 = \frac{3}{2} X 3 + c\\\\-1 = \frac{9}{2}+c\\ \\c = \frac{-2-9}{2} \\\\c = \frac{-11}{2}

Thus, the equation becomes:

y = \frac{3}{2} x - \frac{11}{2}

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Step-by-step explanation:

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