Opposite/adjacent= cosine
cos B= opp/adj
cosB= 7/12
B=cos^-1 (7/12)
(Type it into a graphing calculator)
B=54.3 degrees
Make sure your calculator is in degree mode and you use the inverse cosine.
Answer:
Step-by-step explanation:
Hello!
The variable of interest is the weight in ounces of a soap bar.
Attached is a QQplot diagram.
A Q-Q plot is a diagram that compares two probability distributions, in this case, the probability distribution of the data set against the theoretical normal distribution. If the observed data matches the theoretical sets, you can say that that population follows said distribution.
As you can see in the graphic the observed values (blue dots) fit the normal theoretical quantiles, so we can say that the data appear to come from a normal distribution.
I hope it helps.
It seems you just keep adding 3
-2; 1; 4; 7; 10; 13; 16; 19; 22; 25; 28; 31; 34; 37
37 is the fourteenth term.
The correct model of the height of rocket above water is;
h(t) = -16t² + 96t + 112
Answer:
time to reach max height = 3 seconds
h_max = 256 ft
Time to hit the water = 7 seconds
Step-by-step explanation:
We are given height of water above rocket;
h(t) = -16t² + 96t + 112
From labeling quadratic equations, we know that from the equation given, we have;
a = -16 and b = 96 and c = 112
To find the time to reach maximum height, we will use the vertex formula which is; -b/2a
t_max = -96/(2 × -16)
t_max = 3 seconds
Thus, maximum height will be at t = 3 secs
Thus;
h_max = h(3) = -16(3)² + 96(3) + 112
h_max = -144 + 288 + 112
h_max = 256 ft
Time for it to hit the water means that height is zero.
Thus;
-16t² + 96t + 112 = 0
From online quadratic formula, we have;
t = 7 seconds
