Answer:
I think the answer is 22% but I am not sure
Step-by-step explanation:
Percentage solution with steps:
Step 1: We make the assumption that 50 is 100% since it is our output value.
Step 2: We next represent the value we seek with X
Step 3: From step 1, it follows that 100%=50
Step 4: In the same vein, x%=11.
Step 5: This gives us a pair of simple equations:
100%=50(1).
X%=11(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the left hand side of both equations have the same unit; we have
100% / X% = 11 / 50
X = 22%
Step 7: Taking the inverse (or reciprocal) of both sides yields
X% / 100% = 11 / 50
Therefore, 11 is 22% of 50.
Answer:
Y=10x
(multiply 10 times the salamanders)
Step-by-step explanation:
a formula that can be used for this circumstance is a linear y=mx+b problem. for 1 salamander there are 10 frogs. so with this we can state that y=10x. whatever you plug into the x for the number of salamanders will give you the answer of how many frogs are in the pond. for example.
Y=10x
Y=10(3)
Y=30
30 frogs.
also because 10 is a nice number you can just multiply the number of salamanders times 10. 3*10=30
Answer:
3
Step-by-step explanation:
lim(t→∞) [t ln(1 + 3/t) ]
If we evaluate the limit, we get:
∞ ln(1 + 3/∞)
∞ ln(1 + 0)
∞ 0
This is undetermined. To apply L'Hopital's rule, we need to rewrite this so the limit evaluates to ∞/∞ or 0/0.
lim(t→∞) [t ln(1 + 3/t) ]
lim(t→∞) [ln(1 + 3/t) / (1/t)]
This evaluates to 0/0. We can simplify a little with u substitution:
lim(u→0) [ln(1 + 3u) / u]
Applying L'Hopital's rule:
lim(u→0) [1/(1 + 3u) × 3 / 1]
lim(u→0) [3 / (1 + 3u)]
3 / (1 + 0)
3
Answer: 4 bags
Step-by-step explanation: since the height of the wooden boxes are 1.5 feet tall and they need the box to be full it will be 4 bags. Also because each bag contains 1.5 feet of dirt and that’s the exact amount we need for one box.
