Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call 
quarters, 
nickels and 
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
There are 5 nickels.
Now, we use this value to find the number of quarters
There are 13 quarters.
Also, 
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
Decimals that contain a zero in the tenth position can be thought of as a fraction over 100 as the tenth isn't occupied and the hundredth correlates to the 100 as a denominator. The same goes for a number with the tenth position occupied. These decimals would be put over 10 as they are occupying that position in the decimal.
H + c = 605
c = h + 55
h + h + 55 = 605
2h + 55 = 605
2h = 605 - 55
2h = 550
h = 550/2
h = 275 <== there were 275 hamburgers sold on Friday
c = h + 55
c = 275 + 55
C = 330...there were 330 cheeseburgers sold on Friday
Answer:
The experimental probability would be equal to the number of times the event happened over the number of times it was attempted. In this case, the experiment was tried 48 times, and only 6 times did it land on 2. The experimental probability is 6/48, which simplified to 1/8.
The 4-liter acid material was a lower concentration than 40%. Call it 4 liters of x percent acid.
4x+10*40
————— =30
X+10
