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ryzh [129]
3 years ago
13

Given the functions f(x)=2x^2-3x-8 and g(x)=3x2+5x+1

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

B

Step-by-step explanation:

the product (2x² - 3x - 8)(3x² + 5x + 1) is required

multiply each term in the second factor by each term in the first factor.

= 2x²(3x² + 5x + 1) - 3x(3x² + 5x + 1) - 8(3x² + 5x + 1) ← distribute

= 6x^{4} + 10x³ + 2x² - 9x³ - 15x² - 3x - 24x² - 40x - 8

collecting like terms gives

6x^{4} + x³ - 37x² - 43x - 8 → B


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Find the sum of the first 40 even positive integers.
Pachacha [2.7K]

Answer:

1640

Step-by-step explanation:

Even, positive integers

2+4+6+8+10+12+14+16+18+20+22+24+26+28+30+32+34+36+38+40+42+44+46+48+50+52+54+56+58+60+62+64+66+68+70+72+74+76+78+80 = 1640

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andrew-mc [135]

Answer:

5.7 \times  {10}^{ - 3}

Step-by-step explanation:

0.0057

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final answer

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another example and it will be clear

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final answer

4.03 \times {10}^{ - 5}

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