Question

Given the functions f(x)=2x^2-3x-8 and g(x)=3x2+5x+1

Answer 1

Answer:

B

Step-by-step explanation:

the product (2x² - 3x - 8)(3x² + 5x + 1) is required

multiply each term in the second factor by each term in the first factor.

= 2x²(3x² + 5x + 1) - 3x(3x² + 5x + 1) - 8(3x² + 5x + 1) ← distribute

= 6$x^{4}$ + 10x³ + 2x² - 9x³ - 15x² - 3x - 24x² - 40x - 8

collecting like terms gives

6$x^{4}$ + x³ - 37x² - 43x - 8 → B