All categories

3 years ago

How do you solve this?

Mathematics

2 answers:

MariettaO [177]3 years ago

6 0

Hello there!

We are given a function below:

$\displaystyle \large{f(n) = - 7n + 4}$

To find f(-10), substitute n = -10.

$\displaystyle \large{f( - 10) = - 7( - 10) + 4}$

Evaluate the f(-10)

$\displaystyle \large{f( - 10) = 70 + 4}$

Recall

Negative × Negative = Positive

Therefore,

$\displaystyle \large{f( - 10) = 74}$

f(-10) = 74

Let me know if you have any questions!

Topic: Functions

zavuch27 [327]3 years ago

3 0

Answer:

f(- 10) = 74

Step-by-step explanation:

To find f(- 10) , substitute n = - 10 into f(n) , that is

f(- 10) = - 7(- 10) + 4 = 70 + 4 = 74

You might be interested in

What % more than 80 is more than 104

crimeas [40]

130 i think let me know if this is right

5 0

3 years ago

Explain your answer

N76 [4]

x is equal to - 2/3 after collecting like terms

5 0

3 years ago

Determine the answer to 3 + -5 and explain the steps using a number line

Marizza181 [45]

Adding a positive to a negative, you would look at the number with the greater absolute value, and that number would determine the sign of the sum.

5 - 3 = 2

Since 5 is bigger, you use that sign

-5

-2

Answer: -2

6 0

3 years ago

Read 2 more answers

8/9 + (-5/6) _________ 1/6

Bezzdna [24]

Hellloooooooodoodordododododod

4 0

3 years ago

Simplify give ur answer in index form.

kherson [118]

$\frac{( {j}^{4} \: \times \: {j}^{8}) ^{3} }{( {j}^{9} \: \div \: {j}^{2}) ^{2} }$

First we calculate the product of the denominator.

$\frac{( {j}^{12}) ^{3} }{( {j}^{9} \: \div \: {j}^{2}) ^{2} }$

Then we calculate the quotient of the numerator.

$\frac{( {j}^{12}) ^{3} }{( {j}^{7}) ^{2} }$

We multiply the exponents of the expression.

$\frac{ {j}^{36} }{ {j}^{14} }$

We divide.

$\boxed{ \bold{ {j}^{22} }}$

<h3>MissSpanish</h3>

3 0

2 years ago