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velikii [3]
4 years ago
11

What is the quotient of 14.2 ÷ 0.28

Mathematics
2 answers:
EastWind [94]4 years ago
7 0
50.7 would probly be the quotent
Elina [12.6K]4 years ago
4 0
This would be 50.71                  
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2(x+5) + 2 = 3 ( 2x - 4)
White raven [17]
2x+10+2=6x-12
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6 0
3 years ago
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For the polynomial below, -2 is a zero.
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

please note -2 is not a zero ,it should be 2 is a zero.

by synthetic division

2|  1  4 -10 -4

  |      2  12  4

  |----------------

     1  6   2  | 0

x²+6x+2=0

x=\frac{-6 \pm \sqrt{36-8} }{2} \\or~x=\frac{-6 \pm2\sqrt{7} }{2} \\or ~x=-3\pm \sqrt{7} \\h(x)=(x-2)(x^2+6x+2)=(x-2)(x-3+\sqrt{7} )(x-3-\sqrt{7})

7 0
3 years ago
The height of a small rock falling from the top of a 124-ft-tall building with an initial downward velocity of –30 ft/sec is mod
Contact [7]

Answer:

Option 3.

Step-by-step explanation:

The given function is

h(t)=-16t^2-30t+124

where, h(t) is the height of a small rock falling from the top of a 124-ft-tall building and t is the time in seconds.

It is a downward parabola.

Equate the function equal to 0, to find the time at which the rock touch the ground.

-16t^2-30t+124=0

If ax^2+bx+c=0, the according to the quadratic formula

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

Using quadratic formula, we get

t=\dfrac{-(-30)\pm \sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=\dfrac{30+\sqrt{(-30)^2-4(124)(-16)}}{2(-16)},\dfrac{30-\sqrt{(-30)^2-4(124)(-16)}}{2(-16)}

t=-3.875, 2

Time cannot be negative. So, the rock remain in the air in the interval 0 < t < 2.

Therefore, the correct option is 3.

6 0
3 years ago
Assume u4 is not a linear combination of {u1,u2,u3}
Feliz [49]

Answer:

A. {u1,u2,u3,u4} is a linearly independent set of vectors unless one of {u1,u2,u3} is the zero vector.

Step-by-step explanation:

Given that u4 is not a linear combination of {u1,u2,u3}

This means there is no possibility to write u4 = au1+bu2+cu3 for three scalars a,b,and c.

This gives that u_4-au_1-bu_2-cu_3 \neq 0

This implies that these four vectors are not linearly dependent but linearly independent.

Hence option a is right.

A. {u1,u2,u3,u4} is a linearly independent set of vectors unless one of {u1,u2,u3} is the zero vector.

8 0
3 years ago
50 POINTS PLS Help me pls
zimovet [89]

Answer:

The answer is D

Step-by-step explanation:

5 over 9 would be located in between 0.75 and 8 over 9

8 0
3 years ago
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