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notka56 [123]
3 years ago
8

61/100,0.65,61.5 least to greatest

Mathematics
1 answer:
wariber [46]3 years ago
3 0
61/100 = 0.61
so 
the least is 61/100 then 0.65 and then 61.5 last
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A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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3 years ago
The equation of a line XY is (y-3)=3/2(x-4) what is the slope of the line perpendicular to XY?
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Answer:

It must be 3/2.........

3 0
2 years ago
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What two numbers multiply to get 40 and add to get 11
Trava [24]
I got the factors of 40 but both numbers do not add up to 11. Negative numbers are not considered because the product and sum are positive numbers.

1 x 40 = 40    1 + 40 = 41
2 x 20 = 40    2 + 20 = 22
4 x 10 = 40    4 + 10 = 14
5 x   8 = 40    5 +   8 = 13

I also got the addends of 11 and solved each set to get the product
1 + 10 = 11    1 x 10 = 10
2 +   9 = 11    2 x   9 = 18
3 +   8 = 11    3 x   8 = 24
4 +   7 = 11    4 x   7 = 28
5 +   6 = 11    5 x   6 = 30
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Answer:

A) - 8 - 13 +4

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9(n+3)=7n-3 Help Me Find "X"
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9(n+3)=7n-3

1) distribute 9 into (n+3)

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2) subtract 7n on both sides

2n+27=-3

3) subtract 27 on both sides

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4) divide by 2

n=-15
8 0
3 years ago
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