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1 year ago

The equation v=68t represents the number of views v for a video after t hours. Identify the independent and dependent variables.

Mathematics

1 answer:

stich3 [128]1 year ago

8 0

Answer(s):

Dependent variable: v
Independent variable: t

What is the dependent variable of an equation?

The dependent variable of an equation is the variable that is completely isolated on one side.

What is the independent variable of an equation?

The independent variable is the variable that is not isolated. The independent variable can either have a cooeficient or has some operation (+ - × ÷) included on that side of the equation.

Determining the independent and dependent variable

In this equation, we can see that "v" is completely isolated on one side and "t" has a cooeficient of 68. Thus, the dependent variable is "v" and the independent variable is "t".

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Can someone turn 1938 into a scientific notation for me? 10 POINTS

photoshop1234 [79]

Answer:

1.938 x 10^3

Step-by-step explanation:

1938 move decimal 3 times to left and times by 10 to 3rd

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2 years ago

Read 2 more answers

Bruh can someone answer this I’ll give brainliest

3241004551 [841]

It’s a ! you add both of the numbers to get your missing perimeter.
I’m very sorry if it’s wrong but this is what I believe! stay safe

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2 years ago

If a 171 mile trip took 9 1/2 gallin of gas how much gas is needed for a 247-mile trip?

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2 years ago

g A population is infected with a certain infectious disease. It is known that 95% of the population has not contracted the dise

trasher [3.6K]

Answer:

There is approximately 17% chance of a person not having a disease if he or she has tested positive.

Step-by-step explanation:

Denote the events as follows:

D = a person has contracted the disease.

+ = a person tests positive

- = a person tests negative

The information provided is:

$P(D^{c})=0.95\\P(+|D) = 0.98\\P(+|D^{c})=0.01$

Compute the missing probabilities as follows:

$P(D) = 1- P(D^{c})=1-0.95=0.05\\\\P(-|D)=1-P(+|D)=1-0.98=0.02\\\\P(-|D^{c})=1-P(+|D^{c})=1-0.01=0.99$

The Bayes' theorem states that the conditional probability of an event, say A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B|A)P(A)+P(B|A^{c})P(A^{c})}$

Compute the probability that a random selected person does not have the infection if he or she has tested positive as follows:

$P(D^{c}|+)=\frac{P(+|D^{c})P(D^{c})}{P(+|D^{c})P(D^{c})+P(+|D)P(D)}$

$=\frac{(0.01\times 0.95)}{(0.01\times 0.95)+(0.98\times 0.05)}\\\\=\frac{0.0095}{0.0095+0.0475}\\\\=0.1666667\\\\\approx 0.1667$

So, there is approximately 17% chance of a person not having a disease if he or she has tested positive.

As the false negative rate of the test is 1%, this probability is not unusual considering the huge number of test done.

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2 years ago

Write an expression that can be used to determine the total cost of buying g pounds of granola for $3.25 per pound and f pounds

aivan3 [116]

Answer:

3.25g + 0.74f = t

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2 years ago