Answer:
The minimum sample size we should anticipate using is 601.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
We have no history with this characteristic, so we have no idea as to what the proportion might be.
This means that we use , which is when the largest sample size will be needed.
95% confidence level
So , z is the value of Z that has a pvalue of , so .
What is the minimum sample size we should anticipate using?
This is n for which M = 0.04. So
Rounding up, 601
The minimum sample size we should anticipate using is 601.
Answer:
12.30
Step-by-step explanation:
1.30x4=5.20
54.40-5.20=49.20
49.20/4= 12.30
Answer:
66.8421% decrease
Step-by-step explanation:
I think it’s im not sure 400x