Answer:
c
Step-by-step explanation:
Answer:
((1 4/5) feet) + ((1 5/8) feet) =
3.42500 feet (3 feet 53⁄32 inches)
Step-by-step explanation:
((1 4/5) feet) + ((1 5/8) feet) =
3.42500 feet (3 feet 53⁄32 inches)
Answer:
1. P(X=0)=0.135
2. P(T>1)=0.271
Step-by-step explanation:
1. Let X be the number of accidents in the next year. Find the distribution of X and calculate P(X=0).
The rigth distribution to describe this type of event as number of accidents per unit of time is the Poisson distribution.
![P(x=k)\frac{\lambda^ke^{-\lambdat}}{k!}](https://tex.z-dn.net/?f=P%28x%3Dk%29%5Cfrac%7B%5Clambda%5Eke%5E%7B-%5Clambdat%7D%7D%7Bk%21%7D)
In this case k=0 accidents, parameter λ=2 events/year and t=1 year:
![P(X=0)=\frac{2^0e^{-2}}{0!}=\frac{1*e^{-2}}{1} = 0.135](https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5Cfrac%7B2%5E0e%5E%7B-2%7D%7D%7B0%21%7D%3D%5Cfrac%7B1%2Ae%5E%7B-2%7D%7D%7B1%7D%20%3D%200.135)
2. Let T be the amount of time until the next accident. Find the distribution of T and calculate P(T>1).
In this case, the time between events can be best described by an exponential distribution:
![P(X>t)=e^{-\lambda t}](https://tex.z-dn.net/?f=P%28X%3Et%29%3De%5E%7B-%5Clambda%20t%7D)
In this case parameter λ=2 events/year and t=1 year:
![P(X>1)= e^{-2}=0.271](https://tex.z-dn.net/?f=P%28X%3E1%29%3D%20e%5E%7B-2%7D%3D0.271)
If im correct the answer should be 5
Answer:
(-2, -4)
Step-by-step explanation:
3(-2) - -4 = -2, so it doesn't work.
both equations are the same line