Write a system of linear inequalities representing by the graph.

A new car usually costs £8500. Henry gets a discount of £1000. What is the discount as a percentage of the the usual cost? Give

PtichkaEL [24]

Answer:

the answer is 8500×0.1177= 1000.45

0.1177%

6 0

3 years ago

Please help!!!!!!!!!!!

marishachu [46]

Answer:

23.4

Step-by-step explanation:

you use the equation for pythagorean theorem which is a^2+b^2=c^2 and plug in 12 and 18 into the a and b values to get 15^2+18^2=c^2 then you find the numbers squared so 225+324=c^2 add. 549=c^2 find square root. 23.4 rounded.

8 0

3 years ago

Read 2 more answers

Total = $5.33 Tax rate = 8% How much was the item?

kow [346]

Answer:

42.64

Step-by-step explanation:

6 0

3 years ago

GIVING A BRAINLIST PLZZ ASAP

Jobisdone [24]

Answer:

(c) $3,93 more

(b) Mr. Sánchez's class earned more money.

(a) $\displaystyle [42, 37] → [j, p]$

Step-by-step explanation:

{79 = p + j

{118,17 = 1,65p + 1,36j

−25⁄34[118,17 = 1,65p + 1,36j]

{79 = p + j

{−86 121⁄136 = −1 29⁄136p - j >> New Equation

__________________________

$\displaystyle \frac{-7\frac{121}{136}}{-\frac{29}{136}} = \frac{-\frac{29}{136}p}{-\frac{29}{136}}$

$\displaystyle 37 = p$ [Plug this back into both equations above to get the j-value of 42]; $\displaystyle 42 = j$

The next step is to plug the solution into the BOTTOM EQUATION to calculate the total money earned for each class:

Sánchez's class

$\displaystyle 61,05 = [37][1,65]$

Altogether, thirty-seven fruit pies cost $61,05.

Kelly's class

$\displaystyle 57,12 = [42][1,36]$

Altogether, forty-two bottles of fruit juice cost $57,12.

* Based on the calculation, it is perfectly clear that Mr. Sánchez's class earned more money by $3,93:

$\displaystyle 3,93 = -57,12 + 61,05$

I am delighted to assist you anytime my friend!

6 0

3 years ago

A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compareover the inte

Kobotan [32]

To check the decay rate, we need to check the variation in y-axis.

Since our interval is

$-2We need to evaluate both function at those limits.At x = -2, we have a value of 4 for both of them, at x = 0 we have 1 for the exponential function and 0 to the quadratic function. Let's call the exponential f(x), and the quadratic g(x).[tex]\begin{gathered} f(-2)=g(-2)=4 \\ f(0)=1 \\ g(0)=0 \end{gathered}$

To compare the decay rates we need to check the variation on the y-axis of both functions.

$\begin{gathered} \Delta y_1=f(-2)-f(0)=4-1=3 \\ \Delta y_2=g(-2)-g(0)=4-0=4 \end{gathered}$

Now, we calculate their ratio to find how they compare:

$\frac{\Delta y_1}{\Delta y_2}=\frac{3}{4}$

This tell us that the exponential function decays at three-fourths the rate of the quadratic function.

And this is the fourth option.

4 0

1 year ago