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andreev551 [17]
2 years ago
9

When Jonas does his math homework, he spends an average of 4 minutes on each problem. Last night he spent 1.8 hours on his non-m

ath homework, plus he completed 12 math problems. Approximately how much time did Jonas spend in total on all of his homework last night?
Mathematics
1 answer:
Natali [406]2 years ago
6 0

Answer:

2.6 hours.

Step-by-step explanation:

That would be 1.8 hours plus 4 * 12 = 48 minutes.

48 minutes = 48/60 = 0.8 hours.

Total is 1.8 + 0.8 = 2.6 hours.

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Can someone please help me
Genrish500 [490]

Answer:

c

Step-by-step explanation:

come on ! you can literally see that in the chart.

how many parts of the gray 3/8 are covered by the gray 1/4 ?

2 parts = 2/8 are clearly covered by 1/4.

2/8 is what part of 3/8 ?

it is the same question as "2 is what part of 3" ?

is 2 a quarter (1/4) of 3 ? no, 1/4×3 = 3/4 and not 2.

is 2 one third (1/3) of 3 ? no, 1/3 of 3 = 1/3×3 = 1 and not 2.

is 2 two thirds (2/3) of 3 ? ah, 2/3 × 3 = 2. that is correct !

is 2 three quarters (3/4) of 3 ? no, 3/4×3 = 9/4 and not 2.

once you have the same denominator, you can easily compare the numerators and ignore the denominators for such problems.

8 0
3 years ago
D-7 =-18<br> What’s the answer?
AlexFokin [52]

Answer:

D = - 9

Step-by-step explanation:

D - 7 = -18

D - 7 + 7 = -18 + 7

D = -9

5 0
2 years ago
Read 2 more answers
What are the answers for these questions 1,2,&amp;3
ValentinkaMS [17]
1fyjoite yuuic hyrsd hui
6 0
3 years ago
Six times a number is greater than 20 more than that number. What are the possible values of that number?
Alex73 [517]

Answer:

6x > x + 20,

x > 4

or

X belongs to a set of real numbers [0, +infinity)

Step-by-step explanation:

6x > x + 20

5x > 20

x > 4

3 0
3 years ago
Special air bags are used to protect scientific equipment when a rover lands on the surface of Mars. On Earth, the function appr
PSYCHO15rus [73]

The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.

<h3>What is the approximation about?</h3>

From the question:

Mars: F(x) = 2/3\sqrt{64x}

Therefore, If x = 15

Then:

f (15) =  2/3 \sqrt[8]{15}

= 16/3\sqrt{15}

= 20.7ft/s

Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.

Learn more about Estimation from

brainly.com/question/24592593

#SPJ1

8 0
2 years ago
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