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mash [69]
2 years ago
10

Can anyone pleasse help me this is due tmorrow please i beg

Mathematics
1 answer:
Elis [28]2 years ago
6 0

Answer:

What is the question

Step-by-step explanation:

idk the question so, idk the answer

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Which is the best estimate for the average rate of change for the quadratic function graph on the interval 0 ≤ x ≤ 4?
tatuchka [14]

Answer:

The best estimate for the average rate of change is -2

Step-by-step explanation:

we know that

the average rate of change using the graph is equal to

\frac{f(b)-f(a)}{b-a}

In this problem we have

f(a)=f(0)=0  

f(b)=f(4)=-8

a=0

b=4

Substitute

\frac{-8-0}{4-0}=-2

4 0
3 years ago
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Katie has 36 coins in her jar (nickels, dimes, and quarters) totalling $4.20. She has twice as many dimes as quarters. How many
Diano4ka-milaya [45]

Answer:

I think you need to mutply those. And you will get your answer.

Step-by-step explanation:

4 0
3 years ago
Helpppppppppppppppppppp
lesya [120]

Answer:

• An angle

Step-by-step explanation:

A line, line segment, ray are named by two points

A plane is named by 4 points

3 0
2 years ago
PLz help me this is 7th grade math
UkoKoshka [18]

Answer:

g = 118°, h = 62°, k = 140°, m = 40°

Step-by-step explanation:

g = 118°

h = 180 - 118 = 62°

k = 140°

m = 180 - 140 = 40°

5 0
3 years ago
A single microvillus is a rod-like structure that is 1.0 μm in height. It has a hemispherical top approximately 0.1 μm in diamet
gregori [183]

Answer:

so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).

First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.

so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662μm^{2}.

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3 years ago
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