Label the 3 distinct sides of the box. I arbitrarily chose the letters a, b and c.
Use the info about areas as follows:
ab=54 in^2
ac=90 in^2
bc=60 in^2
Here you have 3 equations in 3 unknowns (a, b and c), which is enough info to use to determine a, b and c. Then the volume of the box is a*b*c.
Example: bc = 90, but c = 60/b. You could subst. 60/b for c in the 2nd and 3rd equation, which will eliminate c completely and leave you with 2 equations in 2 unknowns.
Continuing this procedure, I determined that a=9, b=6 and c=10. Thus, the volume of the box is V = 9*6*10 = 540 cubic inches (answer)
10-
15 + 15 = 30
11 + 11 = 22
30 + 22 = 52
52 + 9 = 61
11-
11 + 10 + 16 = 37
Answer:
Step-by-step explanation:
Jack makes a cuboid. If the length is <em>l</em>, the width is <em>w</em> and the height is <em>h</em>, then its volume is
The height is determined by the side of the square cut out of each corner.
Along the length of the width, the length of two sides of the square are cut.
