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dexar [7]
4 years ago
9

Simplify the expression. A.12 B.25 C.55 D.108

Mathematics
1 answer:
Readme [11.4K]4 years ago
3 0
The answer is B)25.
first you finish the brackets then multiply the answer with 5/9

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4x+(7-3)5=10 please help with this one
Ostrovityanka [42]

Answer:

x=-2.5

Step-by-step explanation:

4x+(7-3)5=10

4x+(4)5=10

4x+20=10

subtract 20 from each side

4x=-10

divide each side by 4

x=-2.5

3 0
3 years ago
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I have been stuck on this question and i would like to know how to solve it ?
LenaWriter [7]
<span>Find the actual walking time of Mama
 = 1 hr
then
Mama spends a total of 1 hr not walking
Not walking time = walking time
therefore
After two min of walking (x), she rests two minutes
x = 2</span>
7 0
4 years ago
Identify the FIVE numbers which have a square root that lies between the whole numbers 4 and 12 (Does not im
AysviL [449]

Answer:

25,16,121,49

5 is the sqaure root of 25 4 is the sqaure root of 16 11 is the square root of 121 and 7 is the square root of 49

50,145,20, and 8 do not have square roots.

6 0
4 years ago
What is 43.29 rounded to the nearest 10th
FinnZ [79.3K]
Hello,

The answer is "40.30".

Reason:

First you fine the tenths place:

43.29

Then look at the number next to it:

43.29

Its greater than 5 therefore it does round:

=40.30

If you need anymore help feel free to ask me!

Hope this helps!
3 0
3 years ago
Read 2 more answers
A college is creating a new rectangular parking lot. the length is 0.17 mile longer than the width and the area of the parking l
Svetradugi [14.3K]
Let's call the width of the parking lot w.
The length of the parking lot if .17 more than the width so the length is w + .17

The parking lot is rectangular so its area is found by multiplying the length and the width. That is, the area is equal to what we obtain when we multiply w by w+.17. The area is: A = w(w+.17)= w^{2} +.17w

We are also told that the area is equal to .039 square miles so we set the expression we obtained for the area equal to .039 as follows.

w^{2} +.17w=.039

Since w represents the width of the rectangular lot, we can solve this equation for w to find the width. This is a quadratic equation (the highest exponent of the variable w is 2). We solve these by setting them equal to zero and then using the quadratic formula.

Setting our equation equal to zero (subtract .039 from both sides) gives us:
w^{2} +.17w-.039=0

The quadratic formula is as follows. Since the equation is in terms of w we write it as "w = ..." instead of the usual "x = ..."

w= \frac{-bplusminus \sqrt{ b^{2} -4ac} }{2a}

The part I write as "plusminus" is typically written with a + sign over a - sign. For right now let's leave it at that. Later in the problem we will see what it means and what to do with it.

To use the formula we have to identify a, b and c.

a is the coefficient of the squared term. That is, the number in front of w^{2} which here is 1.

b is the coefficient of the linear term. That is, the number in front of w which here is .17

c is the constant (the number by itself0 which is -.039

So we have:
a=1
b=.17
c=-.039

We plug these into the quadratic formula to obtain:
w= \frac{-.17plusminus \sqrt{ .17^{2} -(4)(1)(-.039)} }{(2)(1)}
w= \frac{-.17plusminus \sqrt{ .0289+.156} }{2}
w= \frac{-.17plusminus \sqrt{ .189} }{2}
w= \frac{-.17plusminus.43} {2}

Here is where the "pluminus" comes in. We continue to simplify the expression on the right but we split it in two. In one case we use "plus" and in the other "minus". That is, we add in one and subtract in the other. This gives us:
w= \frac{-.17+.43}{2}= \frac{.26}{2}=.13
and
w= \frac{-.17-.43}{2}= \frac{-.6}{2}=-.3

w is the width of the rectangular lot so it is a distance and cannot be measured using negative numbers. The width of the rectangular must be positive so we disregard the negative answer.

The width of the rectangle is .13 miles

Recall that the length of the rectangle is .17 more than the width. That is, the length is w+.17 and as we know the width to be .13 miles the length is .13 + .17 = .3 miles

The answer therefore is:
width = .13 miles
length = .3


4 0
3 years ago
Read 2 more answers
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