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Ket [755]
3 years ago
5

When 33 is added to a number the result is 13 more than 5 times the number.

Mathematics
2 answers:
RoseWind [281]3 years ago
5 0
X - the number

x+33=5x+13 \\
x-5x=13-33 \\
-4x=-20 \\
x=\frac{-20}{-4} \\
x=5

The number is 5.
jek_recluse [69]3 years ago
4 0
<span>When 33 is added to a number, x+33 
the result is 13 more than 5 times the number: 
x+33=5x+13 

THE ANSWER IS IN THE PICTURE DOWN BELOW.

I WROTE IT SOMEWHERE ELSE JUST TO SEE WHAT TO DO BUT I WAS TOO LAZY TO REWRITE IT ALL HERE SO I JUST TOOK A SCREENSHOT. BUT ANYWAYS HOPE THIS HELPS!!!!!!! :)

</span>

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Answer:

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Step-by-step explanation:

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7 0
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Evaluate each of the following. (a) P(11,5) (b) C(11,5) (a) P(11,5) = (Simplify your answer.) (b) C(11,5) = (Simplify your answe
Hunter-Best [27]
<h2>Answer:</h2>

(a)   P(11,5)= 55440

(b)  C(11,5)=462

<h2>Step-by-step explanation:</h2>

We know that the permutation is the number of ways of arranging r items out of a total of n items and is given by:

P(n,r)=\dfrac{n!}{(n-r)!}

and the combination is the number of ways of choosing r items out of a total of n items and is given by:

C(n,r)=\dfrac{n!}{r!\times (n-r)!}

(a)

               P(11,5)

P(11,5)=\dfrac{11!}{(11-5)!}\\\\P(11,5)=\dfrac{11!}{6!}\\\\P(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{6!}\\\\P(11,5)=11\times 10\times 9\times 8\times 7\\\\P(11,5)=55440

(b)

                 C(11,5)    

C(11,5)=\dfrac{11!}{5!\times (11-5)!}\\\\C(11,5)=\dfrac{11!}{5!\times 6!}\\\\C(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{5\times 4\times 3\times 2\times 1\times 6!}\\\\C(11,5)=462

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