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Naddika [18.5K]
3 years ago
9

Solve (t-5) = 2 where t is a real number. Simplify your answer as much as possible.

Mathematics
1 answer:
In-s [12.5K]3 years ago
7 0

Answer:

7

Step-by-step explanation:

T-5=2 2+5=7

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What value of a make the equation 14-a=19-12
abruzzese [7]

14-a=19-12\\14-a=7\\a=14-7\\a=7

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2 years ago
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John had 5/8 of a pizza left after a party. He gave 3/8 of a pizza to his friends to take home and kept the rest.
lorasvet [3.4K]

I'm assuming your trying to find how much pizza he has left.

 You need to subtract the two fractions because the denominators are already the same.

When subtracting fractions, you leave the denominator and regularly subtract the numerator.

Your answer will be 2/8 which equals 1/4th 

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3 years ago
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Find any 3 (x,y) pairs that are solutions for the equation 2x-5y=10 . Show your work
Alla [95]

Answer:

(0,-2), (5,0) and (10,2).

Step-by-step explanation:

Given equation is 2x-5y=10.

Now we need to find 3 pairs of solutions in (x,y) form for the given equation.

As 2x-5y=10 is a linear equation so we are free to pick any number for x like x=0, 5, 10

Plug x=0 into 2x-5y=10, we get:

2(0)-5y=10

0-5y=10

-5y=10

y=\frac{10}{-5}

y=-2

Hence first solution is (0,-2)

We can repeat same process with x=5 and 10 to get the other solutions.

Hence final answer is (0,-2), (5,0) and (10,2).

5 0
3 years ago
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Please I need help ASAP<br>pls explain your answer ​
USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

7 0
2 years ago
In parallelogram DEFG if m&lt; GDE=50° find m
spin [16.1K]

Answer:

130°

Step-by-step explanation:

180-50=130°

4 0
2 years ago
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