Answer:
60/120/180
Step-by-step explanation:
Either of these would work because it must be an even number divisible by 2.
It must end in a zero : divisible by 5 but even.
It must be a multiple of 30 as 3 only goes into 10s at 30. And that takes care of the 6 too.
But 4 doesn't go into 30, so 60?….
Yes, 60 is divisible between 2, 3, 4, 5 and 6
But the question does not limit your answer to one solution.
I hope this helps! :)
Halving-reduce by half or think what is fifty% of the number or divide by two
doubling-add the number you got to the same number or multiply by two
Halving Ex.:6/2=3
Doubling ex.: 9+9=18 or 6*2=12
Answer:
x=4
Step-by-step explanation:
If you plug this in, you get 3(4-2)2=12. Simplify to 3 times 2 times 2, which equals 12. Stay Safe and Have a Magnificent Day!!!!!!;):)
Answer:
The correct answer is option C. 3/5= 0.60
Step-by-step explanation:
It is given that,the Venn diagram shows sports played by 10 students.
event A = The student plays basketball.
event B = The student plays soccer
<u>To find P(A|B))</u>
P(A) = 6
P(B) = 5
P(A ∩ B) = 3
We have P(A|B) = P(A ∩ B)/P(B)
= 3/5
= 0.6
Therefore the correct answer is option C. 3/5= 0.60
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
