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Mademuasel [1]
3 years ago
12

In simplest radical form what are the solutions to the quadratic equation 0=-3x^2-4x+5

Mathematics
2 answers:
TiliK225 [7]3 years ago
6 0
This is a quadratic equation with coefficients a= -3, b= -4 and c= 5.  Thus, the discriminant  b^2-4ac is      (-4)^2 - 4(-3)(-4)  =  16-48 = 16(1-3) = 16(-2).

The solutions are
       -(-4) plus or minus sqrt(discriminant)
x = ---------------------------------------------------
                        2(-3)
          4 plus or minus sqrt(16[-2])
   = -----------------------------------------
                           -6
         4 plus or minus 4*i*sqrt[2]
   = ---------------------------------------
                            -6

This reduces to:
 
       -2  plus or minus i*2*sqrt[2]
x = --------------------------------------            (answers)
                     3
emmasim [6.3K]3 years ago
3 0
Well first you have to find the solution, before you can put it in RADICAL FORM
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First, we estimate the value of √38. √38 is between √36 and √49, but close to √36 (since 38 is closer to 4 than it is to 9). Since √36 is 6, √38 is probably something like 6.1 or 6.2. Filling 6.2 in the expression and simplifying, we have this:

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Answer

Without a calculator we find that 3 - √38 ≅ -3.2.

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