3 years ago

Solve: x^3 - (3x)^2 + x - 3 < 0I know the answer is x < 3, but I don't know how to solve.

1 answer:

6 0

<span>x^3 - 3(x)^2 + x - 3 < 0
х</span>²(х-3)+(х-3)<0
(x-3)(x²+1)<0
x²+1 always more than zero
therefore (x-3)(x²+1)<0 when x-3<0, x<3

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