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3 years ago

A class has 6 boys and 15 girls.What is the ratio of boys and girls?

Mathematics

1 answer:

Sidana [21]3 years ago

8 0

So if boys is 6 and girls is 15 it would be 6/15, but that can be simplified to 2/5.

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3 years ago

A softball pitcher has a 0.507 probability of throwing a strike for each pitch. If the softball pitcher throws 15 pitches, what

jekas [21]

Answer:

P(X > 8) = 0.323

Step-by-step explanation:

We are given that a softball pitcher has a 0.507 probability of throwing a strike for each pitch. Also, the softball pitcher throws 15 pitches.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 15 pitches

r = number of success = more than 8

p = probability of success which in our question is probability of

throwing a strike for each pitch, i.e., 0.507

<em>LET X = Number of strikes</em>

So, it means X ~ $Binom(n=15, p=0.507)$

So, Probability that more than 8 of them are strikes = P(X > 8)

P(X > 8) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{9}0.507^{9} (1-0.507)^{15-9} +\binom{15}{10}0.507^{10} (1-0.507)^{15-10}+\binom{15}{11}0.507^{11} (1-0.507)^{15-11}+\binom{15}{12}0.507^{12} (1-0.507)^{15-12}+\binom{15}{13}0.507^{13} (1-0.507)^{15-13}+\binom{15}{14}0.507^{14} (1-0.507)^{15-14}+\binom{15}{15}0.507^{15} (1-0.507)^{15-15}$ = $5005 \times 0.507^{9} \times 0.493^{6} +3003 \times 0.507^{10} \times 0.493^{5} +1365 \times 0.507^{11} \times 0.493^{4} +455 \times 0.507^{12} \times 0.493^{3} +105 \times 0.507^{13} \times 0.493^{2} +15 \times 0.507^{14} \times 0.493^{1} +1 \times 0.507^{15} \times 0.493^{0}$

= 0.323

Therefore, probability that more than 8 of them are strikes is 0.323.

4 0

3 years ago