Hey there!
when x = 3 and y = 9
Let's first move to x and y.
Now multiply 5 by x and y(3+9).
Now we have the number 2 left, so we have to multiply 60 by 2.
Hope this helps!
After picking apples at the orchard, you made these observations: Brad picked twice as many apples as you did, Andy picked 20 fe
1 answer:
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<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation is zero
<u>Solution:</u>
For a Quadratic Equation of form : ---- eqn 1
The solution is
Now , the given Quadratic Equation is ---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In ,
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation
Since -3 is less than 0, this means that there are 0 real solutions in this equation.
Answer:
x+y=0 and 3x-2y=10
Step-by-step explanation
Let the numbers be x and y.
The sum of the two numbers is 0
Letting the smaller number be y and the
larger number be x:
twice the smaller number
Also, 3 times the larger number
Now ,twice the smaller number subtracted from 3 times the larger number is 10.
Therefore the equations are
and