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Olegator [25]
3 years ago
15

Simplfy : (8(x-1)^2)/ (6(x^2-1))

Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0
Hope it cleared your doubt.

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Jolene invests her savings in two bank accounts, one paying 4 percent and the other paying 10 percent simple interest per year.
Nostrana [21]

Answer:

<h2>$ 22200 in higher yielding bank and $ 44400 in lower yielding bank</h2>

Step-by-step explanation:

       Jolene invests in two bank accounts. The first account gives a 4% interest per year and the second bank gives a 10% interest rate per year.

       She puts twice as much in the lower yielding bank account. Let us denote the amount put in high yielding bank account by x. Lower yielding bank account will have 2x.

       Interest\text{ }per\text{ }year=Principal\times Interest\text{ }rate

Interest from lower yielding bank = \dfrac{4}{100} \times 2x=\dfrac{8x}{100}

Interest from higher yielding bank = \dfrac{10}{100} \times x=\dfrac{10x}{100}

Total Interest per year = $ 3996 = \dfrac{8x}{100} +\dfrac{10x}{100}=\dfrac{18x}{100}

x=22200 \$

∴ Jolene invested $ 22200 in higher yielding bank and $ 44400 in lower yielding bank.

4 0
3 years ago
Find the range of the function. ƒ(x) = x2 + 3
beks73 [17]

Answer:

c

Step-by-step explanation:

7 0
2 years ago
What is the theoretical probability of rolling anything other than a two on a fair six sided die?
mrs_skeptik [129]

Answer:

5/6 probability

Step-by-step explanation:

6 0
2 years ago
If g(x) = 10 - 2x then which of the following is the value of g(7)?
slega [8]

Answer:

g(7)= -4

Step-by-step explanation:

10-2(7)

10-14

=-4

4 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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