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mamaluj [8]
3 years ago
11

Square root of 15-x=-3+Square root of 2x+3 Solve for x

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
5 0

\sqrt{15-x}=-3\sqrt{2x+3}\impliedby \textit{divide by -3}
\\ \quad \\
\cfrac{\sqrt{15-x}}{-3}=\sqrt{2x+3}\impliedby \textit{squares both sides}
\\ \quad \\
\left( \cfrac{\sqrt{15-x}}{-3} \right)^2=(\sqrt{2x+3})^2\implies 
\cfrac{(\sqrt{15-x})^2}{(-3)^2}=(\sqrt{2x+3})^2
\\ \quad \\
\cfrac{15-x}{9}=2x+3\impliedby \textit{multiply both sides by 9}
\\ \quad \\
15-x=18x+27\impliedby \textit{solve for "x"}
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Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and 51\frac{1}{3} yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from 51\frac{1}{3} yards.

\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}

Let us have a common denominator.

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}  

\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}

\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}

\text{1 yard}=3\text{ feet}

\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}

\frac{28}{3}\text{ yards}=28\text{ feet}

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

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Step-by-step explanation:


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Step-by-step explanation:

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3 years ago
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