Answer:
-0.3n + 0.6
Step-by-step explanation:
if we write out the entire expression we have:
0.5n - 0.3 - 0.8n + 0.9 (two negative signs create a positive sign)
then we add and subtract
and receive
-0.3n + 0.6
9m-28=2m
9m-28-2m=2m-2m
(9m-2m)-28=0
7m-28=0
7m-28+28=0+28
7m=28
(7m)/7 = 28/7
m=4
<u>Question 8</u>
a^2 + 7a + 12
= (a+3)(a+4)
When factorising a quadratic, the product of the two factors should equal the constant term (12), and the sum of the two factors should equal the linear term (7). To find the two factors, list out the factors of 12 (1x12, 2x6, 3x4) and identify the pair that adds up to 7 (3+4).
An alternative method if you get stuck during your exam would be to solve it algebraically using the quadratic formula and then write it in the factorised form.
a = (-7 +or- sqrt(7^2 - 4(1)(12)) / 2(1)
= (-7 +or- sqrt(1))/2
= -3 or -4
These factors are the negative of the values that would go in the brackets when written in factorised form, as when a = -3 the factor (a+3) would equal 0. (If it were positive 3 instead, then in the factorised form it would be a-3).
<u>Question 10</u>
-3(x - y)/9 + (4x - 7y)/2 - (x + y)/18
Rewrite each fraction with a common denominator so you can combine the fractions into one.
= -6(x - y)/18 + 9(4x - 7y)/18 - (x + y)/18
= (-6(x - y) + 9(4x - 7y) - (x + y)) /18
Expand the brackets and collect like terms.
= (-6x + 6y + 36x - 63y - x - y)/18
= (29x - 58y)/18
= 29/18 x - 29/9 y
Answer:
340
Step-by-step explanation:
340.33 and rounfing off whole number is 340
Answer:
3
Step-by-step explanation:
there you go pal :)))))
