Answer:
9
Step-by-step explanation:
it's an isosceles right ∆.
so (9√2)^2 = 81*2= 162 = 2s^2
let x=y=s
s^2 = 81
s = 9
Answer:
see below
Step-by-step explanation:
Part A: (72)^x = 1
Take the log base 72 of each side
log72(72^x) = log 72(1)
We know log a^b = b log a
x log72(72) = log72(1)
x = log72(1)
x = 0
Part A: (70)^x = 1
Take the log base 70 of each side
log70(70^x) = log70(1)
We know log a^b = b log a
x log70(70) = log70(1)
x = log70(1)
x = 0
1.The measure of center that is most appropriate for this situation is the MEDIAN. This is because, one of the number given is an outlier, that is, it is much greater than the rest of the given numbers. If the mean of the number given is calculated, it will be discovered that the mean value obtained is higher than most of the scores in the data set, thus,the mean is not a suitable measure of central tendency in this case.
2. To find the median of the given numbers, arrange them in a descending order and add the two numbers in the middle then divide the value by 2.
That is, 0, 0, 1, 1, 2, 2, 2, 14.
The two numbers in the middle is 1 and 2.
Median = [1 + 2] / 2 = 3/2 = 1.5
Therefore, the median is 1.5
Answer: what is the question?
Step-by-step explanation:
GCF of 14 and 56 is 14 and a^2 and a is a, b^4 and b^2 is b^2 by this we know that the answer should be d 14ab^2c