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3 years ago

Find the perimeter and area of the figure:

Mathematics

2 answers:

blagie [28]3 years ago

6 0

Answer:

The primeter is 12 inches

The area is 9 square inches

Step-by-step explanation:

The area of a square is calculated by multiplying side length by itself (all four side lengths would be same for square)

so the area is 3 × 3 = 9 square inches

The primeter is calculated by multiplying side length by 4

so the primeter is 4 × 3 = 12 square inches

erastova [34]3 years ago

3 0

The perimeter is 12 and the area is 9

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3 years ago

What P:X equals 4 let q:y equals -2 which represents if x = 4 then y = -2

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3 years ago

Each time Sarah went to the Candy Shoppe, she bought b bags of M&Ms. Write an expression for how many bags she will buy if s

andrey2020 [161]

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1 year ago

Can someone help me with this

mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

${(x + 2)}^{2} + {(y + 3)}^{2} = 4$

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

$d = \sqrt{(x1 - x2) {}^{2} + {(y1 - y2)}^{2} } \\ r = \sqrt{ {( - 2 - 0)}^{2} + {( - 3 - ( - 3))}^{2} } \\ r = \sqrt{ {( - 2)}^{2} + {( - 3 + 3)}^{2} } \\ r = \sqrt{ {4}^{2} + 0 } \\ r = \sqrt{4} \\ r = 2$

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

$(x - h) {}^{2} + {(y - k)}^{2} = {r}^{2}$

${(x - ( - 2))}^{2} + {(y - ( - 3))}^{2} = {r}^{2}$

${(x + 2)}^{2} + {(y + 3)}^{2} = 4$

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0

2 years ago

−4x+7y+5=0<br> x−3y=−5<br> <br><br> How many solutions does the system have?

xeze [42]

Solution:

Using Substitution Method:

-4x+7y=-5 (Equation 1)

x-3y=-5 (Equation 2)

get the value of x from Equation 2

x=3y-5 (Equation 3)

Put the value of x from Equation 3 in Equation 1

-4(3y-5)+7y=-5

-4(3y)+20+7y=-5

-12y+7y=-5-20

-5y=-25

Negative sign on both sides cancels each other

y=25/5

y=5

Putting value of y in equation 3

x=3(5)-5

x=15-5

x=10

Therefore, [x,y]=[10,5]

Using Elimination Method

-4x+7y=-5 (Equation 1)

x-3y=-5 (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

-4(x-3y)=-5*4

-4x+12y=20 (Equation 3)

Adding Equation 1 and 3

-4x+7y=-5

-4x+12y=20

+ - = - (Change Of Sign with x and y terms)

-----------------

0x-5y = -25

-5y=-25

y=5

Substituting y’s value is Equation 1

-4x+7(5)=-5

-4x+35=-5

-4x=-40

Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

3 0

3 years ago