All categories

2 years ago

Which number is greater? a. 3/8 or 1/4

Mathematics

2 answers:

Nezavi [6.7K]2 years ago

3 0

Answer: 1/4

Step-by-step explanation:

Brilliant_brown [7]2 years ago

3 0

Answer:

1/4<3/8

1/4=2/8

2/8<3/8

You might be interested in

In a simple random sample of 14001400 young people, 9090% had earned a high school diploma. Complete parts a through d below.

ratelena [41]

Answer:

(a) The standard error is 0.0080.

(b) The margin of error is 1.6%.

(c) The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d) The percentage of young people who earn high school diplomas has increased.

Step-by-step explanation:

Let p = proportion of young people who had earned a high school diploma.

A sample of n = 1400 young people are selected.

The sample proportion of young people who had earned a high school diploma is:

$\hat p=0.90$

(a)

The standard error for the estimate of the percentage of all young people who earned a high school diploma is given by:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Compute the standard error value as follows:

$SE_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=\sqrt{\frac{0.90(1-0.90)}{1400}}\\$

$=0.008$

Thus, the standard error for the estimate of the percentage of all young people who earned a high school diploma is 0.0080.

(b)

The margin of error for (1 - α)% confidence interval for population proportion is:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

Compute the critical value of z for 95% confidence level as follows:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\times SE_{\hat p}$

$=1.96\times 0.0080\\=0.01568\\\approx1.6\%$

Thus, the margin of error is 1.6%.

(c)

Compute the 95% confidence interval for population proportion as follows:

$CI=\hat p\pm MOE\\=0.90\pm 0.016\\=(0.884, 0.916)\\\approx (88.4\%,\ 91.6\%)$

Thus, the 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

(d)

To test whether the percentage of young people who earn high school diplomas has increased, the hypothesis is defined as:

H₀: The percentage of young people who earn high school diplomas has not increased, i.e. p = 0.80.

Hₐ: The percentage of young people who earn high school diplomas has not increased, i.e. p > 0.80.

Decision rule:

If the 95% confidence interval for proportions consists the null value, i.e. 0.80, then the null hypothesis will not be rejected and vice-versa.

The 95% confidence interval for the percentage of all young people who earned a high school diploma is (88.4%, 91.6%).

The confidence interval does not consist the null value of p, i.e. 0.80.

Thus, the null hypothesis is rejected.

Hence, it can be concluded that the percentage of young people who earn high school diplomas has increased.

8 0

2 years ago

Eric gets a 7 percent commission for each electronic item he sells .If he sells 3000 worth of elections ,how much commission doe

Bas_tet [7]

Answer:

$210

Step-by-step explanation:

He makes 7% of that which is:

$0.07*3000 = 210$

So, he makes $210 in commission.

8 0

3 years ago

Read 2 more answers

Help I can't fail! pleaseeeee

VLD [36.1K]

Answer:

Step-by-step explanation:

I believe it's C.33 because if 4×33=132 the rest are smaller and one of the is equal,

So in my opinion It's 33

5 0

2 years ago

What is (1.2 x 10^-2) x (3 x 10^5)

liraira [26]

Answer:

B. 3.6 x 10^3

Step-by-step explanation:

(1.2 x 10^-2) x (3 x 10^5)

When we multiply terms with powers , we multiply the factors out front and add the exponents

a * 10^b * c* 10^d = ac * 10^(b+d)

(1.2 x 10^-2) x (3 x 10^5) = (1.2* 3) * 10^(-2+5)

= 3.6 * 10 ^3

6 0

2 years ago

Find the area of the triangle below. Be sure to include the correct unit in your answer.

OleMash [197]

Answer:

area of triangle= 1/2*h*b

= 1/2*6*16

=3*16

= 48 yd²

This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

5 0

2 years ago