Answer:
The brown-eyed parents must be HETEROZYGOUS to produce a blue-eyed child
Explanation:
This question involves a single gene coding for eye color in humans. The allele for brown eyes (B) are dominant over the allele for blue eyes (b). This means that an individual that is heterozygous (Bb) will phenotypically have a brown eyes.
According to this question, a blue-eyed child (bb) will be produced when two brown-eyed parents are HETEROZYGOUS (Bb) for the eye color trait. This means that each of the parent donated the recessive allele (b) to produce the (bb) offspring. Please find the punnet square attached.
Answer:
I want to say the answer is Electric Current
Similar DNA may support "common" ancestry. ☺
High pressure to low pressre
Answer:
See the answer below
Explanation:
1. <u>Only one phenotype</u> is present in the F1 generation offspring. Since tallness was dominant over shortness, all the offspring in the F1 generation appeared tall.
2. <u>Two phenotypes </u>are present in the F2 generation - 9 tall and 3 short. The short trait reappeared at the F2 generation.
3. The genotype of the F1 offspring would be heterozygous. Assuming the purebred tall is AA and the purebred short is aa:
AA x aa
Aa Aa Aa Aa
All the F1 offspring will appear tall and their genotypes would be heterozygous.
4. Assuming that the allele for height is denoted with A (a), <u>the genotype of the purebred tall plant would be AA. </u>
5. In a similia vein, <u>the genotype of the purebred short plant would be aa. </u>