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3 years ago

Find the GCF of 36m and 12. Simple, yes, but I don't know if the variable has to do anything with it.

1 answer:

8 0

12 is a factor of both 36m and 12, but 'm' isn't.
So 12 is the GCF of both 36m and 12.

If you were to factor the GCF out of their sum,
you'd have
12(3m + 1) .

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Answer:

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Step-by-step explanation:

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3 years ago

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The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Artemon [7]

Answer:

P(X $\geq$ 74) = 0.3707

Step-by-step explanation:

We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.

Let X = Score of golfers

So, X ~ N( $\mu=73,\sigma^{2}=3^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 73

$\sigma$ = standard deviation = 3

So, the probability that the score of golfer is at least 74 is given by = P(X $\geq$ 74)

P(X $\geq$ 74) = P( $\frac{X-\mu}{\sigma}$ $\geq$ $\frac{74-73}{3}$ ) = P(Z $\geq$ 0.33) = 1 - P(Z < 0.33)

= 1 - 0.62930 = 0.3707

Therefore, the probability that the score of golfer is at least 74 is 0.3707 .

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3 years ago

Can someone help with explain how to do these, with formulas or techniques?

Otrada [13]

I hope this helps you

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