well, Marcus and Ben are both 5 feet tall and a little bit more, Marcus is 19/24 more and Ben is 9/16 more, so the 5's in the fraction are the same, so which one is larger, 19/24 or 9/16?
we can simply put both fractions with the same denominator, by <u>multiplying one by the other's denominator</u>, so let's proceed,

the value of c that makes the expression a perfect square binomial is c=4 .
<u>Step-by-step explanation:</u>
Here we have , an expression x2 + 4x + c or ,
. We need to find the value of c that makes the expression a perfect square binomial. Let's find out:
We have , 
⇒ 
⇒ 
Now , we know that 
Comparing above equation , to
we get ;
⇒
{
}
⇒ 
⇒ 
Therefore , the value of c that makes the expression a perfect square binomial is c=4 .
Answer:
Step-by-step explanation:
a) Area of white square = side *side = 8 * 8 = 64 sq.mm
Area of 4 white square = 4 * 64 = 256 sq.mm
compound shape
length = 3 cm = 30 mm
Width = 2 cm = 20 mm
Area of compound shape = length *width = 30 * 20 = 600 sq.mm
Area of the shaded part of the compound shape =
Area of compound shape - Area of 4 white square
= 600 - 256
= 344 sq.mm
b) Perimeter of compound shape = 2*(length + width)
= 2*(30 +20)
= 2* 50
= 100 mm
Answer:
70
Step-by-step explanation:
Area equals bh
(4x)(-3x^8)(-7x^3)
4 (-3)(-7) = 84
x(-x^8)(-x^3) = x^(1 + 8 + 3) = x^12
Answer: 84x^12