1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mars1129 [50]
3 years ago
8

If a car travels 400m in 20 seconds how fast is it going

Mathematics
1 answer:
Burka [1]3 years ago
5 0

Answer:

20 m/s

Step-by-step explanation:

Distance = rate * time

400 m = rate * 20 seconds

Divide each side by 20 seconds

400m/ 20 seconds = rate

20 m/second = rate

You might be interested in
What are the vertices of A'B'C if ABC is dilated by a scale factor of 2?
malfutka [58]

The vertices of A'B'C' if A(0, 10), B(8, 6), C(4, 2) is dilated by a scale factor of 2 are;

  • C. A'(0, 20), B'(16, 12), C'(8, 4)

<h3>Which method can be used to find the vertices of A'B'C'?</h3>

Given that triangle ABC is dilated by a scale factor of 2, we have;

A'B' = 2 × AB

A'C' = 2 × AC

B'C' = 2 × BC

Length of AB = √((8-0)^2 + (6-10)^2) = 4•√5

Length of AC = √((4-0)^2 + (2-10)^2) = 4•√5

Length of BC = √((8-4)^2 + (6-2)^2) = 4•√2

By multiplying the given coordinates by the scale factor, we have;

A' = 2 × (0, 10) = (0, 20)

B' = 2 × (8, 6) = (16, 12)

C' = 2 × (4, 2) = (8, 4)

A'B' = √((16-0)^2 + (12-20)^2) = 8•√5

A'C' = √((8-0)^2 + (4-20)^2) = 8•√5

B'C' = √((16-8)^2 + (12-4)^2) = 8•√2

Therefore when we have;

A'(0, 20), B'(16, 12), C'(8, 4), we get;

  • A'B' = 2 × AB
  1. A'C' = 2 × AC
  2. B'C' = 2 × BC

The correct option is therefore;

  • C. A'(0, 20), B'(16, 12), C'(8, 4)

Learn more about finding the distance between points on the coordinate plane here:

brainly.com/question/7243416

#SPJ1

5 0
1 year ago
Help ill give brainly
earnstyle [38]

Answer:

The answer would be 26%

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the value of 2^-3 times 3^-2
andreyandreev [35.5K]

Answer:

Step-by-step explanation:

2^-3=1/2^3

3^-2=1/3^2

(2^-3)(3^-2)=1/72

7 0
3 years ago
Find the solution to the initial value problem
Karo-lina-s [1.5K]

Answer:

y = (11x + 13)e^(-4x-4)

Step-by-step explanation:

Given y'' + 8y' + 16 = 0

The auxiliary equation to the differential equation is:

m² + 8m + 16 = 0

Factorizing this, we have

(m + 4)² = 0

m = -4 twice

The complimentary solution is

y_c = (C1 + C2x)e^(-4x)

Using the initial conditions

y(-1) = 2

2 = (C1 -C2) e^4

C1 - C2 = 2e^(-4).................................(1)

y'(-1) = 3

y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)

3 = -4(C1 - C2)e^4 + C2e^4

-4C1 + 5C2 = 3e^(-4)..............................(2)

Solving (1) and (2) simultaneously, we have

From (1)

C1 = 2e^(-4) + C2

Using this in (2)

-4[2e^(-4) + C2] + 5C2 = 3e^(-4)

C2 = 11e^(-4)

C1 = 2e^(-4) + 11e^(-4)

= 13e^(-4)

The general solution is now

y = [13e^(-4) + 11xe^(-4)]e^(-4x)

= (11x + 13)e^(-4x-4)

3 0
3 years ago
a Textbook weighs 2.5 pounds. how many kilograms does the textbook weigh? round your answer to the nearest tenth of a pound. one
Rzqust [24]
If you round it to the nearest pound it is 1.1 kg
2.5/2.2 = 1.13....
3 0
3 years ago
Read 2 more answers
Other questions:
  • 8(11-3)-2(4+1) simplify the numerical expression
    8·2 answers
  • Which fraction(s) are equal to the shaded fraction in the picture?<br> (It's problem 2)
    14·2 answers
  • How to round 36,993 to the nearest thousand
    6·1 answer
  • Help me asap..........:
    8·1 answer
  • 9x9 = 81<br> 9<br> 18<br> 27<br> 36<br> 45 <br> 54<br> 63<br> 72<br> 81
    15·1 answer
  • PLEASE HELP IT'S TIMED<br> Order from least to greatest 0, -1.9, -1 4/5, -1/3, and 0.25
    6·2 answers
  • Which relation is not a function?
    7·2 answers
  • What is the slope of a line parallel to y = 4x + 3.​
    7·2 answers
  • Write a sine function that has a midline of 3, an amplitude of 5 and a period of 2/7
    9·1 answer
  • In triangle ABC, what is the measure of b if a = 51, c = 38, and B = 11°?
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!