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scoundrel [369]
3 years ago
14

Is square root of 7 a rational number

Mathematics
1 answer:
MAVERICK [17]3 years ago
5 0

Answer: Yeah its a rational number.

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A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
snow_lady [41]

Your question: A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rate.

Answer: 1730

That's the answer mate, if you need more help or if you need to know how I got the answer.. just message me.

Good luck!

6 0
3 years ago
Which graph represents the solution set of the system of inequalities? {x+y<12 y≥x−4
RSB [31]

Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

5 0
3 years ago
Read 2 more answers
Maurice and Johanna have appreciated the help you have provided them and their company Pythgo-grass. They have decided to let yo
Colt1911 [192]
<span><span>1.A triangular section of a lawn will be converted to river rock instead of grass. Maurice insists that the only way to find a missing side length is to use the Law of Cosines. Johanna exclaims that only the Law of Sines will be useful. Describe a scenario where Maurice is correct, a scenario where Johanna is correct, and a scenario where both laws are able to be used. Use complete sentences and example measurements when necessary.
</span>
The Law of Cosines is always preferable when there's a choice.  There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.

To find a missing side, we use the Law of Cosines when we know two sides and their included angle.   We use the Law of Sines when we know another side and all the triangle angles.  (We only need to know two of three to know all three, because they add to 180.  There are only two degrees of freedom, to answer a different question I just did.

<span>2.An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.
</span>
We'll use the standard parabola, oriented in the usual way.  In that case the directrix is a line y=k and the focus is a point (p,q).

The points (x,y) on the parabola are equidistant from the line to the point.  Since the distances are equal so are the squared distances.

The squared distance from (x,y) to the line y=k is </span>(y-k)^2
<span>
The squared distance from (x,y) to (p,q) is </span>(x-p)^2+(y-q)^2.<span>
These are equal in a parabola:

</span>
(y-k)^2 =(x-p)^2+(y-q)^2<span>

</span>y^2-2ky + k^2 =(x-p)^2+y^2-2qy + q^2

y^2-2ky + k^2 =(x-p)^2 + y^2 - 2qy+ q^2

2(q-k)y =(x-p)^2+ q^2-k^2

y = \dfrac{1}{2(q-k)} ( (x-p)^2+ q^2-k^2)

Gotta go; more later if I can.

<span>3.There are two fruit trees located at (3,0) and (−3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.

4.A pipe needs to run from a water main, tangent to a circular fish pond. On a coordinate plane, construct the circular fishpond, the point to represent the location of the water main connection, and all other pieces needed to construct the tangent pipe. Submit your graph. You may do this by hand, using a compass and straight edge, or by using a graphing software program.

5.Two pillars have been delivered for the support of a shade structure in the backyard. They are both ten feet tall and the cross-sections​ of each pillar have the same area. Explain how you know these pillars have the same volume without knowing whether the pillars are the same shape.</span>
5 0
4 years ago
38.7÷1.29 help I'm stuck
Darya [45]

1.29 can go into 38.7 30 times, Your answer is 30.

5 0
3 years ago
Read 2 more answers
Mo has some sweets. He shares them out between x of his friends in 2 different wys. 7 sweets each with 2 leftover or 6 sweets ea
sveticcg [70]

Answer:

Mo is sharing the sweets between 5 friends

Step-by-step explanation:

An important thing to note is that whichever way Mo shares the sweets, the total number of sweets he has does not change. It means that if he chooses the first method to share the sweets, or the second method, he still has the same number of sweets. This will be helpful in setting up an equation that will help us solve the problem.

If he chooses the first way to share the sweets:

7x + 2 = total number of sweets available.

<em>This is because each of his friends gets 7 sweets each, with 2 leftovers. If we add them up, it will give the total number of sweets available to be shared.</em>

<em />

If he chooses the second way to share the sweets:

6x + 7 = total number of sweets available.

<em>This is because each of his friends gets 6 sweets each, with 7 leftovers. If we add them up, it will give the total number of sweets available to be shared.</em>

<em />

because the total number of sweets do not change, we have

7x +2 = 6x +7

Grouping like terms,

7x - 6x = 7 - 2

x = 5.

Therefore, Mo is sharing the sweets between 5 friends

7 0
3 years ago
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