Given f(x) = x² - 10x + 22, what is the range of f?
1 answer:
Answer:
[-3, ∞)
Step-by-step explanation:
There are many ways to find the range but I will use the method I find the easiest.
First, find the derivative of the function.
f(x) = x² - 10x + 22
f'(x) = 2x - 10
Once you find the derivative, set the derivative equal to 0.
2x - 10 = 0
Solve for x.
2x = 10
x = 5
Great, you have the x value but we need the y value. To find it, plug the x value of 5 back into the original equation.
f(x) = x² - 10x + 22
f(5) = 5² - 10(5) + 22
= 25 - 50 +22
= -3
Since the function is that of a parabola, the value of x is the vertex and the y values continue going up to ∞.
This means the range is : [-3, ∞)
Another easy way is just graphing the function and then looking at the range. (I attached a graph of the function below).
Hope this helped!
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Answer:
Step by step Explanation'
To solve this problem, we will need to apply trial-and-error calculation with the binomial distribution, even though it appears like Central Limit Theorem but it's not.
For us to know the value of C , we will look for a minimum integer such that having 'n' number of high performance level of employee has the probability below 0.01.
Determine the maximum value of C, then the maximum value that C can have is 120/n
Let us represent X as the number of employees with high performance with a binomial distribution of
P =0.02( since the percentage of chance of achieving a high performance level is 2%)
n = 20 ( number of employees who achieve a high performance level)
The probability of X= 0 can be calculated
P( X= 0) = 0.98^n
Summation of P( X= 0)+ P( X= 1)+P( X= 2) will give us the value of 0.993 which is greater than 0.99( 1% that the fund will be inadequate to cover all payments for high performance.)
BUT the summation of P( X= 0)+ P( X= 1) will give the value of 0.94 which doesn't exceed the 0.99 value,
Therefore, the minimum value of integer in such a way that P(X >2) is less than 0.01 have n= 2
then the maximum value that C can have is 120/n