If you're talking about the second part of the question where it asks you which facts you included in your answer, you can choose any of them and it will be counted right.
Answer=10
When rounding to the nearest whole number, we need to look to the number in the tenths place
10.09
If the number is 5 or greater, we round up. If the number is 4 or less, we round down.
The number is 0, so we would round down.
10.09 becomes 10
Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
Hey there! The answer is $40000
<span>A car was sold at $34000. That price was 85℅ of the orginal price.
When we know 85% of the original price we can find 1% of this price by dividing by 85.
1% of the original price = $34000 / 85 = $400
</span>When we know 1% of the original price we can find 100% of this price by multiplying by 100.
100% of the original price = original price = $400 * 100 = $40000
The answer is $40000
~ Hope this helps you!