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3 years ago

Round 10.09 To The Nearest Whole Number

Mathematics

2 answers:

german3 years ago

8 0

It would be 10.
good luck on your test :)

ziro4ka [17]3 years ago

3 0

Answer=10

When rounding to the nearest whole number, we need to look to the number in the tenths place

10.09

If the number is 5 or greater, we round up. If the number is 4 or less, we round down.

The number is 0, so we would round down.

10.09 becomes 10

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Help me determine if relations 1, 2, 3, and 4 are functions or not please!

Reil [10]

They are all not functions

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2 years ago

What is the slope of a line that passes through at (-1,5) and (4,5)

murzikaleks [220]

5-5/4--1= 0/5=undefined slope. This is a line that goes up and down and cannot exist in a function

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3 years ago

A ladder is placed against a wall such that the top is 8 feet above the ground. If the ladder is 10 feet long, how far away from

Annette [7]

Answer:

6 feet

Step-by-step explanation:

Consider the right triangle formed by the wall, ladder and ground.

Let the distance the ladder is from the wall be d , then

Using Pythagoras' identity in the right triangle

The square on the hypotenuse ( ladder) is equal to the sum of the squares on the other 2 sides ( wall and d ), then

d² + 8² = 10²

d² + 64 = 100 ( subtract 64 from both sides )

d² = 36 ( take the square root of both sides )

d = $\sqrt{36}$ = 6

That is the ladder is 6 feet away from the wall

7 0

3 years ago

Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)

Maurinko [17]

Answer:

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

$(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0$

Substituting the end point are

$(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\$

Applying Distributive Property we get

$x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0$

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

6 0

3 years ago

D.) A line that has a slope of 3, and goes through the<br> point (2,8); answer in point-slope form.

PIT_PIT [208]

Answer:

y - 8 = 3(x - 2)

Step-by-step explanation:

Start with the basic point-slope form of the equation of a straight line:

y - k = m(x - h). Here the given point is (2, 8), so assign the value 2 to h and the value 8 to k, also the value 3 to m. Then:

y - 8 = 3(x - 2)

8 0

3 years ago