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katen-ka-za [31]
3 years ago
13

Which represents the inverse of the function f(x) = 4x?

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
7 0
<h3>Answer: D)  h(x) = (1/4)x</h3>

This is the same as h(x) = x/4

In decimal form, it would be h(x) = 0.25x

=============================================

Explanation:

Inverses undo the original function. The original function tells us to take any input (x) and multiply by 4 to get the output y = f(x) = 4x

To get the inverse, we reverse the operation applied here. The opposite of multiplication is division. So we'll divide by 4 instead of multiply by 4. This is why the answer is x/4 or (1/4)x

-----------

Another approach is to do the following: Replace f(x) with y. Swap x and y. Solve for y

f(x) = 4x

y = 4x

x = 4y

4y = x

y = x/4

h(x) = x/4

We end up with the same result as before.

-----------

Extra info:

For any real number x, the following two equations are true

h( f(x) ) = x

f( h(x) ) = x

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1) \chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

2) df = c-1 = 2-1

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Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Tall =30 , Short =20

We need to conduct a chi square test in order to check the following hypothesis:

H0: The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.

H1: The deviations from a 1:1 ratio (25 tall and 25 short) are NOT due to chance.

Part 1

So then we know that the expected values would be 25 for each case

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

And if we replace we got:

\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2

Part 2

For this case the degreed of freedom are given by:

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Where c represent the number of categories c=2

And we can calculate the p value given by:

p_v = P(\chi^2_{1} >2)=0.157

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

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